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练习3

于 2020-06-15 发布
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下载积分: 1 下载次数: 1

代码说明:

说明:  适用于初学者的web网页设计编程的第三部分。(The third part of web page design and programming for beginners.)

文件列表:

day08\.project, 967 , 2016-09-22
day08\01table.html, 708 , 2016-09-22
day08\02regexp.html, 709 , 2016-09-22
day08\03mouseEvent.html, 1099 , 2016-09-22
day08\04keyboard.html, 507 , 2016-09-22
day08\04table3.html, 3230 , 2016-09-22
day08\05formEvent.html, 1237 , 2016-09-22
day08\06equal.html, 1286 , 2016-09-22
day08\addRow.html, 1609 , 2016-09-22
day08\ball.png, 2872 , 2016-09-22
day08\bat.png, 170 , 2016-09-22
day08\brick.png, 2873 , 2016-09-22
day08\game.html, 2739 , 2016-09-22
day08\index.html, 123 , 2016-09-22
day08\js\product.js, 304 , 2016-09-22
day08\打砖块.html, 10308 , 2016-09-23
day09\.project, 967 , 2016-09-23
day09\day9\.project, 966 , 2018-11-03
day09\day9\index.html, 123 , 2018-11-03
day09\game.html, 3400 , 2016-09-23
day09\game重构后.html, 1633 , 2016-09-23
day09\img\ball.png, 2872 , 2016-09-23
day09\img\bat.png, 170 , 2016-09-23
day09\img\brick.png, 2873 , 2016-09-23
day09\index.html, 164 , 2016-09-24
day09\js\ball.js, 860 , 2016-09-23
day09\js\bat.js, 575 , 2016-09-23
day09\js\const.js, 377 , 2016-09-23
day09\js\game.js, 1473 , 2016-09-23
day09\timer.html, 470 , 2016-09-23
day07\.project, 967 , 2016-09-21
day07\01addNode.html, 1942 , 2016-09-21
day07\02table.html, 1578 , 2016-09-21
day07\03table2.html, 3081 , 2016-09-21
day07\04table3.html, 4157 , 2016-09-22
day07\addRow.html, 1606 , 2016-09-22
day07\image\doc.gif, 167 , 2016-09-21
day07\image\fclose.gif, 112 , 2016-09-21
day07\image\fold.gif, 170 , 2016-09-21
day07\image\z-1.jpg, 751 , 2016-09-21
day07\image\z-2.jpg, 723 , 2016-09-21
day07\image\z-3.jpg, 739 , 2016-09-21
day07\image\z-4.jpg, 709 , 2016-09-21
day07\image\z-end.gif, 64 , 2016-09-21
day07\image\z-top.gif, 68 , 2016-09-21
day07\index.html, 123 , 2016-09-21
day07\js\product.js, 304 , 2016-09-21
day07\树形菜单-3.html, 1614 , 2016-09-21
day07\树形菜单-1.html, 3395 , 2016-09-21
day07\树形菜单-2.html, 1602 , 2016-09-21
day09\day9\css, 0 , 2018-11-03
day09\day9\img, 0 , 2018-11-03
day09\day9\js, 0 , 2018-11-03
day08\css, 0 , 2016-09-22
day08\img, 0 , 2016-09-22
day08\js, 0 , 2018-10-27
day09\css, 0 , 2016-09-23
day09\day9, 0 , 2018-11-03
day09\img, 0 , 2018-10-27
day09\js, 0 , 2018-10-27
day07\css, 0 , 2016-09-21
day07\image, 0 , 2018-10-27
day07\js, 0 , 2018-10-27
day08, 0 , 2018-10-27
day09, 0 , 2018-11-03
day07, 0 , 2018-10-27

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    无标度网络结构相对简单,实现算法与可视化并不困难。与其它语言相比,Matlab 语言具有丰富的数学 函数库,能够写出简约的源代码。对于非计算机专业的大学生来说,以此为基础,能够快速进入复杂网络前沿 研究课题,对其数学建模能力和科研能力的培养极为有益。-Scale-free network structure is relatively simple algorithm is not difficult and visualization. Compared with other languages, Matlab language with a rich library of mathematical functions, can be simple to write the source code. For non-computer science students is as a basis to quickly enter the complex network of cutting-edge research topics, their mathematical modeling and scientific research is extremely useful ability.
    2022-01-22 16:22:43下载
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    zoj094 Matrix multiplication problem is a typical example of dynamical programming. Suppose you have to evaluate an expression like A*B*C*D*E where A,B,C,D and E are matrices. Since matrix multiplication is associative, the order in which multiplications are performed is arbitrary. However, the number of elementary multiplications needed strongly depends on the evaluation order you choose. For example, let A be a 50*10 matrix, B a 10*20 matrix and C a 20*5 matrix. There are two different strategies to compute A*B*C, namely (A*B)*C and A*(B*C). The first one takes 15000 elementary multiplications, but the second one only 3500. Your job is to write a program that determines the number of elementary multiplications needed for a given evaluation strategy. (Matrix multiplication problem is a typical example of dynamical programming. Suppose you have to evaluate an expression like A*B*C*D*E where A,B,C,D and E are matrices. Since matrix multiplication is associative, the order in which multiplications are performed is arbitrary. However, the number of elementary multiplications needed strongly depends on the evaluation order you choose. For example, let A be a 50*10 matrix, B a 10*20 matrix and C a 20*5 matrix. There are two different strategies to compute A*B*C, namely (A*B)*C and A*(B*C). The first one takes 15000 elementary multiplications, but the second one only 3500. Your job is to write a program that determines the number of elementary multiplications needed for a given evaluation strategy. )
    2012-06-10 10:38:53下载
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