▍1. c++时尚编程百例__1-20
c++时尚编程百例__1-20(c++ fashional programing sample)
c++时尚编程百例__1-20(c++ fashional programing sample)
c++时尚编程百例__81-110(c++ fashional programing sample)
vc++6.0数据库编程大全一书得各个章节得源码,比较详细.可以仔细参照学习!(Detail codes for each paragraph of <<Full-scale of VC++6.0 data base program>>)
对斐波那契数列取余,输入长度,输出取余结果。(Redundancy of Fibonacci Sequences)
测量字符串长度,输入字符串,输出字符串的长度。(Measure the length of the string, input the string, output the length of the string.)
说明: 对斐波那契数列取余,输入长度,输出取余结果。(Redundancy of Fibonacci Sequences)
说明: 测量字符串长度,输入字符串,输出字符串的长度。(Measure the length of the string, input the string, output the length of the string.)
输入两个数,求他们的最大公约数和最小公倍数。(Enter two numbers to find their maximum common number and minimum common multiple.)
说明: 输入两个数,求他们的最大公约数和最小公倍数。(Enter two numbers to find their maximum common number and minimum common multiple.)
用迭代法求 x=根号a。求平方根的迭代公式为:X(n+1)=(Xn+a/Xn) /2。(Iterative method is used to find x = root a. The iteration formula for finding square root is X(n+1)=(Xn+a/Xn)/2.)
第一行输入灯泡个数,第二行输入灯泡状态。(The first line inputs the number of bulbs, and the second line inputs the bulb status.)
说明: 用迭代法求 x=根号a。求平方根的迭代公式为:X(n+1)=(Xn+a/Xn) /2。(Iterative method is used to find x = root a. The iteration formula for finding square root is X(n+1)=(Xn+a/Xn)/2.)
说明: 第一行输入灯泡个数,第二行输入灯泡状态。(The first line inputs the number of bulbs, and the second line inputs the bulb status.)
C语言程序设计,非常实用,入门级的编程资料(C language programming, very practical, entry-level programming materials)
说明: C语言程序设计,非常实用,入门级的编程资料(C language programming, very practical, entry-level programming materials)
各种C语言基础练习及代码答案,适合C语言初学者。(Basic C language exercises and code answers.)
说明: 各种C语言基础练习及代码答案,适合C语言初学者。(Basic C language exercises and code answers.)