登录
首页 » Visual C++ » maze

maze

于 2011-03-27 发布 文件大小:1KB
0 192
下载积分: 1 下载次数: 0

代码说明:

说明:  由数字1和0组成迷宫,0代表可走路径,程序会用坐标的形式给出每一步的走法(Composed by a maze of numbers 1 and 0, 0 to go the path, the program will use the coordinates given in the form of moves at each step)

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • sstring
    利用串来比较数据大小,代码中有两个串,通过串来比较大小( 10/5000 Use the string to compare the data size)
    2016-12-20 17:05:29下载
    积分:1
  • heapSort.cpp.tar
    这是一个堆排序的算法源程序,算法被单独写成一个函数,希望对大家有用(This is a heap sort algorithm source code, algorithms are written as a separate function, we hope to be useful)
    2013-12-12 14:52:48下载
    积分:1
  • Task1-trial--10211281--zly
    描述:足球俱乐部包括球员、普通行政人员。球员有姓名、年龄、能力、年薪、转会费、进球总数、服役年限等重要参数;普通行政人员有姓名、年龄、能力、年薪等参数。你需要给相关管理机构开发一个管理程序,实现对众多足球俱乐部管理的基本功能。具体功能包括: a) 俱乐部的增删改查,俱乐部的属性包括名称、现金、其下人员; b) 可以对所有球员的各项属性进行简单搜索,支持输入多个条件,条件之间用&&连接,例如: i. “年龄不大于25且服役年限大于5年且进球数大于100的球员”,查询表达式:!(@age>25) && @experience>5 && @kick>100 c) 支持球员在不同俱乐部间的买卖,买卖需符合以下条件:作为买方的俱乐部的现金>=球员的转会费,交易完成后,卖方将得到转会费。 要求: d) 必须采用面向对象的方式,使用类组织数据结构,并注意类的继承关系; e) 在题目要求基础上可以自行扩展功能,提供扩实用扩展功能者适当加分(加分不超过5分)。 (Description: Football club including players, general administrative staff. Player name, age, ability, salary, transfer fee, total number of goals, service life and other important parameters ordinary administrative staff name, age, ability, salary and other parameters. You need to give the relevant management agencies to develop a management program to achieve the number of football club management s basic functions. Specific features include: a) the club CRUD, the name of the club s property, including cash, under which personnel b) all players can perform a simple search of the property, supports input multiple conditions with && connection between conditions, for example: i. "Age is not greater than 25 and greater than 5 years service life and goals more than 100 players," query expression:! (@ age> 25) && @ experience> 5 && @ kick> 100 c) Support the players traded between different clubs, the sale subject to the following conditions: As a buyer s club cash> = pl)
    2013-08-20 10:09:29下载
    积分:1
  • Dijkstra
    迪特斯特拉算法,课程设计的作品,主要计算站点距离的吧,可以看看(Dieter Stella algorithm, distance course design work, the main computing sites can look)
    2013-04-11 10:26:15下载
    积分:1
  • ECSBL
    说明:  该程序实现二叉树的遍历功能,能够打印出二叉树的节点(The program realization of the binary tree traversal function, is capable of printing out the binary tree node)
    2008-11-13 15:50:49下载
    积分:1
  • HuffanCoding
    读取数据,统计所得到的文件中每个字母的权值,创建哈夫曼树,哈夫曼编码。哈夫曼解码,解码后内容写入到指定的文件。 读取数据里面的内容是由英文单词组成。读取文件的时候传入文件存放的路径、读取方式以及读出以后存放的数组,最终可以得到一个存放目标文件内容的数组。 将得到的数组进行字母权值的统计,统计每个字母出现的次数,次数即为每个字母的权值。 将得到的字符数组与权值数组作为创建哈夫曼树的依据,哈夫曼树根据每个字母权值的大小来创建,每个节点,包括权值、父节点、左子、右子和字母本身。 根据哈夫曼树进行编码。形成目标文件的哈夫曼编码,将此编码返回。 根据哈夫曼树得到的数组即为解码数组,解码数组作为解码的结果返回。 写入输出文件,将解码得到的数组、文件的完整路径以及文件的写方式作为参数传入,将数组写入到相应的文件中。 (Read the data, statistical documents obtained weights for each letter, create a Huffman tree, Huffman coding. Huffman decoding, the decoded contents are written to the specified file. Read the content inside is composed of English words. When the incoming file to read the file storage path, read mode and read out after storage array that can eventually get a storage target file contents of the array. The resulting array of letter weights statistics, statistical number of occurrences of each letter, the number is the weight of each letter. The resulting character array with the weights array as the basis for creating Huffman tree, Huffman tree based on the size of the weights of each letter to create, for each node, including weights, parent, left child, right child, and letter itself. According to Huffman coding. The formation of the target file Huffman coding, this code returns. According to Huffman decoding the resulting array is an array, the decoder decodes the result is retur)
    2020-07-02 15:40:01下载
    积分:1
  • migong---cPP
    迷宫问题C++代码。。。解决迷宫问题。。。。(Maze C++ code. . . Solve maze problems. . . .)
    2011-11-03 22:28:30下载
    积分:1
  • examples-of-data-structure
    吴伟民版数据结构每个算法的c实现方法,并模块化处理,将各个功能分开编程,有助于移植使用(failed to translate)
    2013-05-06 13:20:48下载
    积分:1
  • LR(0)
    简单LR语法分析程序自动生成器的实现,可用作数据结构课程设计(LR (0) grammar analysis)
    2013-09-22 09:26:25下载
    积分:1
  • 约瑟夫环的循环链表实现
    约瑟夫环的循环链表实现,这个程序比较完整,有需要做试验的请速速下载。(Josephus cycle Chain achieved, the procedure is complete, the pilot needs to be done urgently requested to download.)
    2005-07-03 19:38:38下载
    积分:1
  • 696518资源总数
  • 105714会员总数
  • 27今日下载