-
一个socket通信服务端代码
一个socket通信服务端代码-a socket communications server code
- 2022-03-13 03:19:36下载
- 积分:1
-
用来进行端口转发。端口映射等功能都可以
C语言源码
格式
110 127.0.0.1 112
本地端口 转发IP 转发端口...
用来进行端口转发。端口映射等功能都可以
C语言源码
格式
110 127.0.0.1 112
本地端口 转发IP 转发端口-Used for port forwarding. Such as port mapping functions can be C language source code format 110 127.0.0.1 112 local port forwarding IP forwarding port
- 2022-12-15 21:25:03下载
- 积分:1
-
the procedures used to establish Socket Interface
该程序使用了Socket接口建立通住双方的TCP连接,从而完成通信.服务器方可以与多个客户端建立连接,并且可以选择要向哪个已建立起连接的客户端发送消息.-the procedures used to establish Socket Interface-living both TCP connections, thus completing communications. Server side with the establishment of a number of client connections and can be chosen which has been established to connect the client send messages.
- 2022-02-20 16:39:39下载
- 积分:1
-
JMT-src-and-libs-0.7.0.tar
一个用于排队系统仿真的开源软件,有非常形象的图象仿真过程!(a queuing system simulation for the revenue-generating software, the image of the very image simulation!)
- 2007-01-21 12:47:45下载
- 积分:1
-
naca-airfoil
生成NACA翼型的vb程序,输入4位数naca翼型,得到翼型剖面。(NACA airfoil generates vb program, enter the 4-digit naca airfoil, get airfoil sections.)
- 2021-04-10 12:08:59下载
- 积分:1
-
FAT32的部分操作C语言实现代码
FAT32的部分操作C语言实现代码.rar是fat32的c语言实现(FAT32 part of Operation C language code. Rar is fat32 in C Language)
- 2021-04-14 13:48:55下载
- 积分:1
-
大家都考三级网络都需要的书,现在一般的三级网络上机题都是在里面找的一些题目,希望能够对大家有帮助...
大家都考三级网络都需要的书,现在一般的三级网络上机题都是在里面找的一些题目,希望能够对大家有帮助-we have obtained three networks are needed, While the three networks on the plane and that they were looking for some topics, we hope to be able to help
- 2022-05-19 12:43:56下载
- 积分:1
-
frp_0.27.0_windows_amd64
说明: Acting for P2P holes, wall piercing artifacts. Support Windows platform, Linux system, etc
- 2020-06-20 14:20:01下载
- 积分:1
-
vs_net_ver298
VS.NET编程源码。包含很多VC++.NET和VB.NET源码(-VS.NET programming source code. It includes a lot source codes of VC++.NET and VB.NET.)
- 2004-05-29 12:41:49下载
- 积分:1
-
实验一
说明: 一般信道容量迭代算法
(1)初始化信源分布:P^((0))=(p_(1 ),p_(2 ),…,p_(i ),…,p_r),置迭代计数器k=0,设信道容量相对误差门限为δ,δ>0,可设C(0)=-∞;
(2)φ_ji^((k))=(p_ij p_i^((k)))/(∑p_ij p_i^((k)) ) i=1,…,r;j=1,…,s;
(3)p_i^((k+1) )=exp?[∑_j?〖p_ij lnφ_ji^((k)) 〗]/(∑_i?〖{exp?[∑_j?〖p_ij lnφ_ji^((k)) 〗]}〗) i=1,…,r;
(4)C^((k+1))=ln∑_i?〖{exp?[∑_j?〖p_ij lnφ_ji^((k)) 〗]}〗;
(5)如果,
(|C^((k+1) )-C^((k)) |)/C^((k+1)) ≤δ,
转向(7);
(6)否则,置迭代符合 k+1→k,转向(2);
(7)输出p_i^((k+1) )和C^((k+1));
(8)停止。(General channel capacity iterative algorithm)
- 2020-05-21 14:30:04下载
- 积分:1