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fmincon
求解非线性方程。调用格式x=fmincon（fun，x0,A,b,Aeq,beq,VLB,VUB)(For solving nonlinear equations. Call the format x = fmincon (fun, x0, A, b, Aeq, beq, VLB, VUB))
- 2009-09-06 13:18:25下载
- 积分：1
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e1
说明： 16点基4—FFT算法编程。输入16点的序列，采用基4-fft方法计算其快速傅里叶变换。(16 points-based 4-FFT algorithm for programming. Enter the 16-point sequence, with the base 4-fft method for calculating the fast Fourier transform.)
- 2010-11-19 18:21:25下载
- 积分：1
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shiyan4
若矩阵A中的某一元素A[i，j]是第i行中的最小值，而又是第j列中的最大值，则称A[i，j]为矩阵A中的一个鞍点。请写出一个可确定此鞍点位置的算法（如果这个鞍点存在）。(If the matrix A, an element A [i, j] is the minimum value in the i-th row, but is the maximum value of the j-th column, then A [i, j] for the matrix A is a saddle point. Please write a algorithm to determine the position of saddle point (saddle point exists).)
- 2013-01-07 13:16:11下载
- 积分：1
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fembem-for-EM-scattering
有限元法边界元法求解二维散射问题，非常有用(Finite element method for solving two-dimensional boundary element method scattering problem, very useful)
- 2021-04-23 19:48:47下载
- 积分：1
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EEHMT0
根据给定的等距结点上的函数值与一阶导数值, 用埃尔米特等距插值公式计算指定插值点处的函数值。(According to the given equidistant nodes function value with a first derivative values, with equidistant interpolation Hermite interpolation formula specified function value at the point.)
- 2013-08-26 15:12:11下载
- 积分：1
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UMAT各页公式详解V2
说明： umat公式详细介绍，我也不知道够20字了mei(the introduction of umat in abaqus)
- 2019-01-14 18:57:58下载
- 积分：1
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MATLAB
利用有限元法计算悬臂梁的实例，包含详细说明，适合用于课程设计。(Using the finite element method to calculate the cantilever instance, contains a detailed description, suitable for curriculum design.)
- 2014-10-04 08:37:38下载
- 积分：1
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ykb
实对称矩阵特征值与特征向量的雅克比法，ap为是对称矩阵，vp返回特征向量(Real Symmetric Matrix Eigenvalues and Eigenvectors of the Jacobian method, ap is a symmetric matrix, vp return eigenvector)
- 2020-08-03 17:18:34下载
- 积分：1
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Trilateration-Network
测绘程序，计算测边网各点坐标的评查程序，值得借鉴(Mapping program to calculate the coordinates of each point measured the side-netting of assessment investigative procedures, worth learning)
- 2013-08-20 15:13:21下载
- 积分：1
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fft13
fft code in visual c++
- 2011-07-16 22:23:05下载
- 积分：1
