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Morphy
mathematical morphology application
- 2013-04-03 22:52:05下载
- 积分：1
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1
说明： 这是基于帧差法对运动目标检测的代码 希望对大家有用(This is based on frame difference of the moving target detection code)
- 2010-08-22 19:49:55下载
- 积分：1
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watermark
说明： 变换域的数字图像水印技术及图像质量评价研究(Study of digital image watermarking in frequency
domain and image quality evaluation
)
- 2010-04-06 18:00:08下载
- 积分：1
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Matlab-FEM
Matlab程序 桁架结果、欧拉梁程序
不错哦(Matlab truss result, Euler beam program
)
- 2011-07-01 17:44:34下载
- 积分：1
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amend-matlab-error
彻底解决Matlab 2008b 及以上版本Simulink 无法直接打开或无法保存含中文字符MDL文件的错误(Completely resolved Matlab 2008b and above Simulink unable to directly open or save a file containing Chinese characters MDL error)
- 2013-03-05 19:03:11下载
- 积分：1
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xiebo
谐波信号提取程序，可以用于信号谐波分量的分离(The harmonic signal extraction procedures, can be used for separation of signal harmonic component)
- 2013-12-09 09:12:55下载
- 积分：1
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EWT
经验小波分解，通过ewt变换分解重构信号，实现对信号的降噪(Experience in wavelet decomposition, reconstruction signal by ewt transformation decomposition, realize the signal noise reduction)
- 2017-02-25 16:46:36下载
- 积分：1
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matlab-5
《Matlab时频分析技术及其应用》(人民邮电出版社)第5章随书程序.("Matlab time-frequency analysis technology and its applications" (People s Posts )
- 2009-01-20 17:07:31下载
- 积分：1
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5
一道程序编译顺序的考题，涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。
C的程序编译总是从main函数开始的，这道题的重点在“fun（（int）fun（a+c,b）,a-c）） ”语句。
系统首先要确定最外层 fun()函数的实参，第一个参数的确定需要递归调用fun()函数（不妨称其为内层函数）。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)
- 2009-03-15 15:36:23下载
- 积分：1
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nnn
求一元二次方程ax2 +bx+c=0的根(Find a quadratic equation ax2+ bx+ c = 0 root)
- 2013-10-10 11:24:33下载
- 积分：1
