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matlab-Getting-Started-classic
MATLAB入门教程,十分适合初学MATLAB者学习使用,内容很详细。(MATLAB Tutorial, very suitable for beginners who learn to use MATLAB, the content is very detailed.)
- 2014-10-29 15:47:00下载
- 积分:1
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cisco_voip.tar
Cisco VoIP decoder Software
- 2015-04-13 08:48:27下载
- 积分:1
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Histogram
柱形统计图,能够直接得出图像的灰度直方图。
里面有程序的源代码(Histogram, can directly draw the image histogram.
There are procedures for source code)
- 2012-04-02 22:23:48下载
- 积分:1
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Appendix2B_neural_netwotk_classifiers
different classifier for matlab
- 2013-09-15 20:08:26下载
- 积分:1
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BPSK_main
BPSK信号的调制和解调,包含卷积编码和解码(BPSK modulation and demodulation of signals, including encoding and decoding convolutional)
- 2011-11-08 21:46:57下载
- 积分:1
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Index-system-as-a-whole-LE
在混沌研究中,求系统整体LE指数的matlab源代码(In the study of chaos, seeking overall system LE index matlab source code)
- 2013-12-07 18:25:07下载
- 积分:1
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hypot
抛物线法求解
方程的构造方法:给出[0,1]区间上的随机数(服从均匀分布)作为方程的根p*.
设你的班级数为a3,学号的后两位数分别为a2与a1,从而得到你的三次方程
例如:你的31班的12号,则你的方程是21x3+60x2+2x+a0=0的形式.
方程中的系数a0由你得到的根p*来确定.(parabolic equation method Construction Methods : given interval [0,1] on the random number (subject to uniform distribution) as the root equation p*. set up your classes at a3, after learning of the double-digit for a1 and a2, so you get the three equations for example : your 31 classes on the 12th, then your equation is 21x3 60x2 2x a0 = 0 forms. the equation coefficients a0 you get from the root of p* to determine.)
- 2014-04-25 08:18:59下载
- 积分:1
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ipexndvi
It is related to image processing
- 2011-06-22 17:23:26下载
- 积分:1
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Finger-Print-SOM
This Is Source Code Finger print With MeThode SOM
- 2012-08-11 19:29:33下载
- 积分:1
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BP11
bp网络实现过程的源代码,用c、c++和matlab编写(bp network process source code, using the c c++ and matlab prepared)
- 2013-04-17 22:20:10下载
- 积分:1