登录
首页 » matlab » ESPRIT_DOA

ESPRIT_DOA

于 2011-04-12 发布 文件大小:1KB
0 248
下载积分: 1 下载次数: 0

代码说明:

说明:  ESPRIT方法进行DOA估计,各种参数见程序内部的参数设置,只是简单的ESPRIT程序,而非修正的ESPRIT方法(ESPRIT DOA estimation methods, see the program within the parameters set of parameters, but simply the ESPRIT program, rather than the ESPRIT method of correction)

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • feinuo
    费诺编码,用MATLAB仿真平台,实现费诺编码的MATLAB仿真研究。(Connaught coding costs by MATLAB simulation platform, to achieve cost Connaught MATLAB simulation code.)
    2010-11-29 11:09:28下载
    积分:1
  • rayleigh
    rayleigh,matlab的仿真,程序简单,容易实现,并易懂(rayleigh, matlab simulation, the program is simple, easy to implement and easy to understand)
    2011-05-03 14:23:50下载
    积分:1
  • vortex
    说明:  有效观察OAM的相位模式,可自由设定拓扑荷数(Observing the phase mode of OAM effectively, the topological charge can be set freely.)
    2021-03-04 16:09:32下载
    积分:1
  • RPEM_Source_Code
    EM算法,基于期望最大化原则进行密度估计(EM algorithm, based on the expectation maximization of the principle of density estimation)
    2007-08-07 17:17:02下载
    积分:1
  • password-generator-
    基于混沌映射的密码生成算法,给定任意一个初值作为密钥,可以产生任意长度的密码,保密性高(password generator based on chaotic map)
    2012-05-09 10:58:17下载
    积分:1
  • DictionaryLearning
    一种基于图像训练的字典构造方法,可以用来进行压缩感知的基矩阵构造(Based on image training dictionary construction method can be used for compressed sensing-based matrix structure)
    2011-08-02 13:21:16下载
    积分:1
  • Motion-DetectionBackgroundSubstruction
    背景帧差法的最简单Matlab源代码,对初学者有很大的启发(Background frame difference Matlab source code for the most simple, a great inspiration for beginners)
    2011-01-07 21:08:42下载
    积分:1
  • GDLSMwk
    通过正交点的寻找从而用几何最小二乘拟合椭圆的方法(Finding points to the orthogonal least squares fitting using the geometric method of elliptic)
    2011-04-19 20:22:44下载
    积分:1
  • k-means
    基于k均值的强化学习的状态和动作的选择,可以有效的解决维灾难问题。(q learning with k-means )
    2012-03-29 21:08:37下载
    积分:1
  • hole_ASM
    用角谱法计算菲涅尔衍射图样,计算出后加上GS算法即可得出全息图(Fresnel diffraction pattern is calculated using the angular spectrum method, after adding GS algorithm to calculate the hologram can be derived)
    2014-09-22 19:50:27下载
    积分:1
  • 696516资源总数
  • 106913会员总数
  • 8今日下载