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CAR
some problems about c++.(car.cpp)
- 2012-01-12 14:39:48下载
- 积分：1
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shizuo
用哈夫曼编码的方式进行图像的压缩，其中定义了一个cdib的类，通过之类来对图像进行处理(image coding in haffman)
- 2012-04-27 18:37:47下载
- 积分：1
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InverseList
说明： 链表逆转,实现单链表的逆转程序，数据结构(List Inverse)
- 2011-04-04 11:15:58下载
- 积分：1
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shiyan1
数据结构上机操作实验的实验1，线性表的基本操作！！！(the basic operation of sq of date structure)
- 2011-12-11 18:49:06下载
- 积分：1
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44
说明： 给定程序中，函数fun的功能是：将a所指3×5矩阵中第k列的元素左移到第0列，第k列以后的每列元素依次左移，原来左边的各列依次绕道右边。
例如，有以下矩阵：
1 2 3 4 5
1 2 3 4 5
1 2 3 4 5
若k结果为2，程序执行结果为：
3 4 5 1 2
3 4 5 1 2
3 4 5 1 2
请在程序的下划线处填入正确的内容并把下划线删除，使程序得出正确的结果。
注意：源文件存放在考生文件夹下的BLANK1.C中
不得增行或删行，也不得更改程序的结构！
(A given program, function fun feature is: a 3 × 5 matrix referred to in the first k elements of the left column to move Section 0, the k elements of each column after column followed by the left, the original columns in the left turn Bypass on the right. For example, the following matrix: 123,451,234,512,345 If k is 2, the program execution results: 345,123,451,234,512 in the program underscore the right content at the fill and to remove the underscore, so that the program reach the right result. Note: The source files in the folder of BLANK1.C candidates are not allowed by the line or delete line, nor change the structure of the program!)
- 2011-08-11 07:53:10下载
- 积分：1
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bintree
一个关于二叉树应用的小程序,包括二叉树的建立，前中后遍历等操作(a program about bintree structure)
- 2009-05-17 16:54:29下载
- 积分：1
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EightQueen
经典的 数据结构问题 八皇后问题。问题是在8*8的棋盘上放置棋子，要求每条直线上不能出现两个或以上的棋子。(The classical data structure problem Eight queens problem.Question is placed on the 8* 8 board piece, requirements on each line cannot appear two or more pieces.)
- 2016-11-23 10:30:11下载
- 积分：1
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zhaose
本代码是通过C语言来实现贪心算法求着色问题,包括具体问题和实现代码(This code is the C language to implement the greedy algorithm for the coloring problem, including specific issues and the implementation code)
- 2013-09-23 16:04:24下载
- 积分：1
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shell
希尔排序，希尔排序，希尔排序，希尔排序，c语言(shell sort)
- 2010-10-30 10:39:13下载
- 积分：1
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jose
约瑟夫环（约瑟夫问题）是一个数学的应用问题：已知n个人（以编号1，2，3...n分别表示）围坐在一张圆桌周围。从编号为k的人开始报数，数到m的那个人出列；他的下一个人又从1开始报数，数到m的那个人又出列；依此规律重复下去，直到圆桌周围的人全部出列。通常解决这类问题时我们把编号从0~n-1，最后结果+1即为原问题的解。
(Josephus (Josephus problem) is the application of a mathematical problem: Given n individuals (with numbers 1,2,3 ... n respectively) sitting around a round table. From the number of people gettin k, number of the m man out of the line he s the next person and a number of gettin number to m the man was out of the line and so the law is repeated until the round table were all out of the column. We numbered 0 ~ n-1, the final result is the original problem solution+1 usually solve these problems.)
- 2015-01-09 17:28:41下载
- 积分：1
