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ss
说明： Source code for subsampling
- 2010-12-29 13:18:13下载
- 积分：1
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matlab
说明： matlab的入门，金典书籍，值得一看。对于新手或刚入门的有很多帮助(matlab entry, Jindian books, worth a visit. For novice or just a lot of help getting started)
- 2008-10-18 00:00:24下载
- 积分：1
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iirtest
用双线性变换法设计IIR数字滤波器,程序，用图形显示(Bilinear transformation method of IIR digital filter design, procedures, graphical display)
- 2011-06-29 20:59:37下载
- 积分：1
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bp
说明： 通过matlab实现iir bandpass滤波器(iir bandpass)
- 2009-06-07 09:56:27下载
- 积分：1
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abaqucongrumendaojingtong
可以很简单明了的了解abaqus的使用，对于新手朋友是很有用的。(Can be very simple and clear understanding of the use of abaqus)
- 2011-01-22 03:48:33下载
- 积分：1
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figure_with_two_axis_with_same_grid
这个脚本绘制了两套相同的两个独立的轴具有相同的网格图上的1D数据。(This script plots two sets of 1D data on the same figure with two separate axis and with the same gridding. )
- 2011-08-25 21:12:04下载
- 积分：1
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Program04
war card game. play war with the computer
- 2014-10-07 22:14:30下载
- 积分：1
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Astar_1
说明： 一种简单的A*寻路算法，可在命令行按要求输入相应起点和终点的坐标。适合于初学者(A simple A* algorithm for path planning, which can input the coordinates of the starting point and end point on the command line as required. It is suitable for beginners.)
- 2019-04-19 15:01:36下载
- 积分：1
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GAFILTER
matlab重要的学习资料 初学者的好帮手 程序代码非常重要 语音信号处理方面应用广泛(matlab important information for beginners to learn a good helper program code is very important speech signal processing is widely used)
- 2010-10-06 19:55:39下载
- 积分：1
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zhaoxiaopu
位置指令为幅值为1.0的阶跃信号，r（k）=1.0。网络结构为1-4-1，高斯函数的参数值取Cj=[-2 -1 1 2]T ，B=[0.5 0.5 0.5 0.5]T 。
网络权值学习参数为η=0.30，α=0.05 。PID控制各参数的初RBF网络控制，被控对象为G（s）=
取采样时间为1ms，采用Z变换进行离散化，离散化后的被控对象为
y(k)=-den(2)*y（k-1）-den(3)*y(k-2)+num(2)*u(k-1)+num(3)*u(k-2)
始值为，kp=20， kd=0.3， ki=0.1。
(Position command for the step signal amplitude of 1.0, r (k) = 1.0. The network structure is 1-4-1, the Gaussian function parameters taken Cj = [-2-1 1 2] T, B = [0.5 0.5 0.5 0.5] T. Weight learning parameter η = 0.30, α = 0.05. PID control parameters at the beginning of each RBF network control, the controlled object is G (s) = take the sampling time is 1ms, using the Z transform discrete, discretized controlled object is y (k) =-den (2)* y (k-1)-den (3)* y (k-2)+num (2)* u (k-1)+num (3)* u (k-2) initial value, kp = 20, kd = 0.3, ki = 0.1.)
- 2013-07-22 21:20:28下载
- 积分：1
