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Josephson
Josephson振子系统,Josephson振子系统,Josephson振子系统,Josephson振子系统,Josephson振子系统,(Josephson oscillators, Josephson oscillators, Josephson oscillators, Josephson oscillators, Josephson oscillator system,)
- 2010-12-03 09:33:16下载
- 积分:1
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mainn
用于绘制滚动轴承故障的频谱图和包络解谱图,从而判断轴承故障(Used to draw the rolling bearing fault frequency spectrum and spectral envelope solutions, in order to determine bearing failure)
- 2021-01-20 16:58:41下载
- 积分:1
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Nakagami_m-SCMRC
nakagami 衰落信道上几种数字调制方式的误码率仿真(the fading channels several digital modulation in nakagami BER simulation)
- 2020-11-23 09:59:35下载
- 积分:1
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feiji
使用GS理论简单实现相位重建的算法,图片包含在内(Simple Phase Reconstruction Using GS Theory)
- 2020-06-21 00:40:02下载
- 积分:1
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jam_sp
说明: 噪声射频干扰信号的matlab仿真实现,其中包含成像的提取程序(SAR radio frequency jamming signal)
- 2020-11-02 11:59:53下载
- 积分:1
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MATLAB6
matlab6.0函数查询手册。使用非常方便,收录了matlab的大部分函数。(Manual query matlab6.0 function. Very convenient to use, includes most of the matlab function.)
- 2009-04-13 13:18:06下载
- 积分:1
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PlateProblem
A Plate Element displacements for effective shear force
- 2010-05-18 02:30:27下载
- 积分:1
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1
说明: simulink simulation in micro converter file
- 2014-11-21 23:43:28下载
- 积分:1
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simulation
在一个移动通信系统中,发射信号是一个未调制的音频x(t)=cos(2πft),其中f=f0+fi。设标称载波为f0=1GHz,并设fi =512Hz。假定移动用户在一个繁忙的高速公路上距离基站l公里处的地方,从开始从每小时60公里的速度开始,其速度(在0.01秒的时间间隔内测量)以1/2的概率随机的增加或减少1/10公里每小时。试仿真移动用户在这2s的时间间隔内所接收到的信号(及其频谱)。接收信号可以表示为:
y(t)=a(t)Cos[2π(fo+f1)(t-△t)]
式中 △(t)=d(t)/c
且 a(t)=k/d2(t)
在上面的表达式中d(t)是在t时刻基站与移动用户的距离,c是光速,△(t)是传播延迟,而a(t)是信号在t时刻的衰减,并假设在这2s内a(t)是一个常数。利用复低通等效模型来进行仿真。(In a mobile communication system, the transmitted signal is an unmodulated audio x (t) = cos (2πft), where f = f0+ fi. Let nominal carrier of f0 = 1GHz, and set fi = 512Hz. Assume that mobile users on a busy motorway station l kilometers place, starting the beginning of 60 kilometers per hour, the speed (measured in 0.01 second interval) to increase the probability of a random 1/2 or reducing 1/10 km/h. Simulation test signal which the mobile subscriber in the 2s time intervals of the received (and its spectrum). The received signal can be expressed as:
y (t) = a (t) Cos [2π (fo+ f1) (t- △ t)]
Where △ (t) = d (t)/c
And a (t) = k/d2 (t)
In the above expression, d (t) at time t is a base station and a mobile user s distance, c is the speed of light, △ (t) is the propagation delay, and a (t) is the attenuation of the signal at time t, and assuming that 2s within a (t) is a constant. Using complex low-pass equivalent model for emulation.)
- 2015-11-24 17:16:20下载
- 积分:1
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ray_qam16
raylian fading for qam 16
- 2010-05-29 14:38:01下载
- 积分:1