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16QAM
this is simulation 16QAM modulation in additive white gaussian noise channel
- 2009-12-18 01:45:26下载
- 积分：1
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sim_dukou
渡口模型，系统模拟仿真，排队论，任意输入船道数和模拟次数，输出平均车辆数和各车辆类型数量(Ferry model, system simulation, queuing theory, any input channel number and the number of simulations ship, the output of the average number of vehicles and the number of vehicle types)
- 2013-09-23 21:47:10下载
- 积分：1
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extractFeatures
用matlab编写的图像特征提取程序，其中包括一个提取8维HSV颜色直方图特征的函数，一个可以批量处理图像的主程序。(Prepared using matlab image feature extraction procedures, including an 8-dimensional HSV color histogram extracted feature functions, one of the main program can batch process images.)
- 2014-01-15 14:58:11下载
- 积分：1
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PLC_model
brewery matlab simulink model
- 2016-05-29 01:10:54下载
- 积分：1
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nanhun
是本科毕设的题目，验证可用，阵列信号处理的高分辨率估计。( The title of the commercial is undergraduate course you Verification is available, High-resolution array signal processing estimates.)
- 2017-01-05 09:38:53下载
- 积分：1
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feijidong_zhong
卡尔曼滤波器运用于目标跟踪，据此编写的对于非机动模型的仿真(Kalman filter used in target tracking, has been prepared accordingly for non-motorized model simulation)
- 2010-01-03 17:05:29下载
- 积分：1
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matlab-optimization
matlab书籍 这是一本优化工具箱基础知识的书 这是本书的第一部分(it is matlab book and you can learn the basic matlab optimization and this is the first part of the book
)
- 2012-03-30 11:00:57下载
- 积分：1
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Sonar_Exp_1_3
声纳技术 常用水声信号及其处理方法 内容：1）CW信号；2）LFM；3）谱分析；4）自相关 (Sonar technology)
- 2020-12-23 10:09:08下载
- 积分：1
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ofdm_gitosimulink
This simulation simulates coded OFDM using RS Code over wireless channel
This simulation simulate wireless Coded OFDM over mobile multipath fading channel. The model use QPSK, Reed-Solomon Channel Coding, and training based channel estimation
(This simulation simulates coded OFDM usin g RS Code over wireless channel This simulation simulate Coded OFDM wireless mobile multi over path fading channel. The model use QPSK. Reed-Solomon Channel Coding, and training based channel estimation)
- 2007-05-10 11:12:21下载
- 积分：1
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example2
利用遗传算法求f(x,y)=x*cos(2*pi*y)+y*sin(2*pi*x),-2<=x<=2,-2<=y<=2的最大值(Using genetic algorithms for f (x, y) = x* cos (2* pi* y)+ y* sin (2* pi* x),- 2 <= x <= 2,-2 <= y <= 2 the maximum)
- 2014-10-01 09:22:24下载
- 积分：1
