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bianjietiaojian
一阶弹性波方程交错网格差分法(时间2阶空间4阶，带边界条件) 最基础的波长快照(Elastic wave equation of first order staggered-grid difference method (time 2-order space of order 4 with boundary conditions) the wavelength of the most basic snapshot)
- 2011-05-08 17:15:12下载
- 积分：1
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nnrbf
pid控制，RBF网络，通过神经网络来对PID的参数进行整定优化。(PID control, RBF network.The parameters of PID are optimized by neural network.)
- 2021-04-09 17:29:00下载
- 积分：1
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chap9_10
基于加权LS-SVM的非线性系统内模控制的仿真程序，由于辨识信号采用的都是随机信号，不是数值固定的信号，所以程序每次运行的结果都可能有所不同(Emulator mode control based on weighted LS-SVM nonlinear systems identification signal are random signal, not the value of the fixed signal, so the program each time you run the results are likely to differ)
- 2013-03-05 21:19:07下载
- 积分：1
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baseline_200702
矩阵变换函数,可通过该函数实现三位是两的绕轴变换(Matrix transformation function, can be accessed through the function of the three two-axis transformation)
- 2008-01-08 01:53:06下载
- 积分：1
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fiber_mode_distribution
多模光纤模式能量分布图形，彩色强度图，十分漂亮(the modes distributions of multi modes in fiber, intensity graphi, very beautiful)
- 2021-01-22 16:38:40下载
- 积分：1
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rayleigh_fading
对无线通信信道中的瑞利衰落进行MATLAB仿真(of wireless communications channel for the Rayleigh fading MATLAB simulation)
- 2006-05-23 16:36:11下载
- 积分：1
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cdma-matlab
对CDMA通信系统进行matlab仿真，包括Viterbi编码（卷积编码），交织，扩频，调制，解调，抽样判决，解偏置,码型转换，解交织等源代码，给出了误码率曲线。(Matlab on the CDMA communication system simulation, including the Viterbi coding (convolutional coding), interleaving, spreading, modulation, demodulation, sampling decisions, solve bias, format conversion, such as source code deinterleave given bit error rate curve.)
- 2011-05-11 00:01:58下载
- 积分：1
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ios---Run-app-for-more-than-10-minutes-in-backgro
Here is a tutorial for iOS development.
If you are going to make the app on background mode, please see this document.
- 2015-03-10 17:22:18下载
- 积分：1
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power_pwm
电力系统脉宽调制波形，经调试改进，绝对正确(power_pwm)
- 2009-04-04 17:00:15下载
- 积分：1
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LTE_System_Level_1.4_r570
To solve this instance of the decision problem we must determine whether there is a truth value (TRUE or FALSE) we can assign to each of the variables (x1 through x4) such that the entire expression is TRUE. In this instance, there is such an assignment (x1 = TRUE,x2 = TRUE, x3=TRUE, x4=TRUE), so the answer to this instance is YES. This is one of many possible assignments, with for instance, any set of assignments including x1 = TRUE being sufficient. If there were no such assignment(s), the answer would be NO.
- 2012-04-23 22:00:12下载
- 积分：1
