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zhuanchakongzhi
转差控制法的matlab模型文件，矢量控制的另一种形式(Matlab model file transfer differential control law)
- 2012-05-21 12:42:49下载
- 积分：1
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powerSpectrumEstimation_APES
APES算法的频率谱估计
包含1个目标信号和2个干扰信号(Frequency Spectrum Estimation of APES Algorithm
Contains one target signal and two interference signals)
- 2017-04-16 17:49:51下载
- 积分：1
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Data-Driven Robust Approximate Optimal Tracking论文的实验示例程序
Data-Driven Robust Approximate Optimal Tracking论文的实验示例程序。(Data-Driven Robust Approximate Optimal Tracking paper experimental sample program.)
- 2020-06-27 00:20:01下载
- 积分：1
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EKFslammatlab
用EKF，在matlat环境下实现的SLAM，包括GUI仿真界面及参考文件(extended Kalman Filter, under matlab environment)
- 2009-03-23 16:42:00下载
- 积分：1
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voicebox
voicebox ,很不错的matlab源程序(voicebox, a very good source matlab)
- 2007-08-03 21:02:51下载
- 积分：1
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leaf
分形树叶生成，分形课程中一定会用到的，非常好的！(fenxingshuye)
- 2010-12-23 11:11:18下载
- 积分：1
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Electric_Circuits_Nilsson_7thSolutionManual(13~17
Linear Signal&System-lathi 1st solution
if you have more question
plase contact pudn s master
- 2012-03-21 15:57:47下载
- 积分：1
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grav_nonlinear
地球物理勘探中重力资料解释的主要目的是由地表观测值推断地下可能存在的密度分布。众所周知,任何一组重力数据都可能由无数个密度分布所引起。即使假设了重力异常是由具有均匀密度差的单一地质体产生的,也得不出唯一的解(Gravity geophysical exploration data interpretation main purpose is inferred from surface observations may exist underground density distribution. Is known, any set of data may be provided by gravity density caused numerous. Even assuming that the gravity anomaly is determined by having a uniform density difference arising from a single geological body, they have no unique solution)
- 2013-11-21 23:46:03下载
- 积分：1
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MATLABR2008
《MATLAB R2008控制系统动态仿真》的配套光盘，不但便于读者使用，而且给任课老师提供了生成数量不限的
练习题的功能，便于因人施教。(" MATLAB R2008 Control System in Dynamic Simulation," supporting CD-ROM, readers not only easy to use, but also to the classroom teacher provides a unlimited number of practice questions generated features, easy to teach from person to person.)
- 2010-07-23 12:51:43下载
- 积分：1
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rk
说明： 用四阶古典RK方法解初值问题：
取h=1/8。每隔8步打印出数值解与真解的值（u(t)=(t^2)/2-t），画出它们的大致图像，并对产生的结果做出解释。
(with four bands classical RK method for initial value problems : from h = 1/8. Every eight-step numerical solution print and in the true value (u (t) = (t ^ 2)/2-t), they generally draw the images, as well as the results of an explanation.)
- 2006-05-27 00:07:17下载
- 积分：1
