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test12
约瑟夫问题，用数据结构的循环链表实现约瑟夫问题的解答(Joseph problems，30 people in a circle, and inspires us with a circular chain to said. Can use structure array to make a cycle chain. The structure has two members, one for pointing down a pointer to a circular chain )
- 2012-05-14 10:29:52下载
- 积分：1
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a-linked-list-and-related-processing
链表的建立及相关处理，包括排序，删除，初始化，增加，删除等等，且程序已运行通过。(The establishment of a linked list and related processing, including sorting, delete, initialization, increase, delete, etc., and the program has been run through
)
- 2014-01-13 23:56:27下载
- 积分：1
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LR(0)
简单LR语法分析程序自动生成器的实现，可用作数据结构课程设计(LR (0) grammar analysis)
- 2013-09-22 09:26:25下载
- 积分：1
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qiuhe
多项式求和，用链表实现的一元多项式求和程序，比较 靠谱(Polynomial sum, with the linked list implementation of a polynomial summation procedure, more reliable)
- 2011-09-15 09:16:38下载
- 积分：1
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sf_2014320164457
数据结构中的许多东西,包括头文件、例题、习题等等(Data structure many things, including the header files, examples, exercises, etc.)
- 2014-04-03 15:24:34下载
- 积分：1
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jose
约瑟夫环（约瑟夫问题）是一个数学的应用问题：已知n个人（以编号1，2，3...n分别表示）围坐在一张圆桌周围。从编号为k的人开始报数，数到m的那个人出列；他的下一个人又从1开始报数，数到m的那个人又出列；依此规律重复下去，直到圆桌周围的人全部出列。通常解决这类问题时我们把编号从0~n-1，最后结果+1即为原问题的解。
(Josephus (Josephus problem) is the application of a mathematical problem: Given n individuals (with numbers 1,2,3 ... n respectively) sitting around a round table. From the number of people gettin k, number of the m man out of the line he s the next person and a number of gettin number to m the man was out of the line and so the law is repeated until the round table were all out of the column. We numbered 0 ~ n-1, the final result is the original problem solution+1 usually solve these problems.)
- 2015-01-09 17:28:41下载
- 积分：1
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Fa_Pai
关于随机发牌算法的小程序，作为数据结构的大作业，开发环境是VC(Random licensing algorithm for small procedures, as big job data structures, the development environment is VC)
- 2014-10-16 17:54:20下载
- 积分：1
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kaikuohaohebikuohaodepipei
开括号和比括号的匹配，数据结构内容，很不错(More than brackets and brackets to open the match, the contents of data structure)
- 2009-04-13 14:35:56下载
- 积分：1
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Huffman-Tree
使用三叉链表实现的哈夫曼树,统计inputfile1.txt中各字符的出现频率，并据此构造Huffman树，编制Huffman 码；根据已经得到的编码，对01形式的编码段进行译码。
具体的要求：
1．将给定字符文件编码，生成编码，输出每个字符出现的次数和编码；
2．将给定编码文件译码，生成字符，输出编码及其对应字符。
(Emergence of the frequency of each character in the trigeminal lists using the Huffman tree, statistics inputfile1.txt, and accordingly the Huffman tree structure, preparation of Huffman code according to the coding has been. 01 to form the code segment for decoding.
Specific requirements:
1 coding the given character file, generating the encoding, and outputting the number and encoding of each character
2 will be given the encoding file decoding, generating the character, the output code and its corresponding character.)
- 2015-05-22 15:37:03下载
- 积分：1
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InverseList
说明： 链表逆转,实现单链表的逆转程序，数据结构(List Inverse)
- 2011-04-04 11:15:58下载
- 积分：1
