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BM3D
The Block-Matching and 3D Filtering (BM3D) algorithm is a computationally scalable algorithm based on this novel denoising strategy. It achieves state-of-the-art denoising performance in terms of both peak signal-to-noise ratio and subjective visual quality.
- 2010-01-08 15:16:09下载
- 积分：1
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MatlabCodeforDeterministicDynamicProgramming
一个决策性动态规划的matlab代码，有参考文献，适合初学者(A dynamic programming decision-making matlab code, there are references for beginners)
- 2008-06-24 20:57:28下载
- 积分：1
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gmresm_mine
计算大型矩阵的一般的gmres算法matlab程序。(large matrix calculation of the general gmres algorithm Matlab procedures.)
- 2007-01-01 16:25:17下载
- 积分：1
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xiaoboboSVMsort
该程序描述了SVM神经网络的数据分类脑电信号种类识别。(The program describes the SVM neural network data classification EEG species identification.)
- 2013-04-26 19:47:40下载
- 积分：1
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matlab_expriment
matlab
包含优化问题试验、微分议程试验、代数实验和综合试验等
(matlab optimization problem that contains test, differential agenda test, algebra test and integrated test)
- 2007-10-29 11:05:55下载
- 积分：1
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addon
addon.m是用matla编写的距离函数和拓扑函数示例(addon.m is prepared with matla topological distance function and the function of the sample)
- 2010-09-20 17:23:33下载
- 积分：1
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gprmax2d_readprofile
一个m函数，可以读取GprMax2d的模型数据，将雷达正演模拟的模型的刨面数据读出来(A function of m, can be read GprMax2d model data, radar forward simulation model of the planing surface data read out)
- 2013-04-07 20:52:07下载
- 积分：1
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dcf-mode-saturated-throughput-analysis
Performance comparison of saturated throughput of CoopMAC and IEEE 802.11 DCF mode. Analytical model used is based on the one described in performance analysis of ieee 802.11 dcf by guisseppe bianchi.
- 2015-02-24 18:19:14下载
- 积分：1
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speech_processing
this program deals with simple speech processing like fft, use of hamming window, my durbin algorithm and likes. this program has gui too.
- 2009-05-13 21:24:36下载
- 积分：1
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MadHG
利用函数MadHG生成规则LDPC码的校验矩阵H，其行重为6,列重为3,行数为列数一半(行数越大越好)，H中任意两列没有围长为4的圈，并得到H对应的生成矩阵G，可以保证mod(G*H ,2)=0。使用方法为:[H,G] = MadHG(m,n,x),x= 1(得到的G左半部分为单位阵) or 2(G右半部分为单位阵),(use function MadHG Generation rules LDPC check matrix H, re-6, series of three, out for a few half of the number (A bigger the better), H 2 arbitrary no girth of the four circles, H counterparts and with the formation of matrix G, we can be assured of mod (G* H, 2) = 0. To be used : [H, G] = MadHG (m, n, x), x = 1 (the G part of the Left Front units) or 2 (G right half of the units RUF),)
- 2007-05-12 10:54:46下载
- 积分：1
