登录
首页 » matlab » acs_assignment4

acs_assignment4

于 2011-05-16 发布 文件大小:667KB
0 212
下载积分: 1 下载次数: 9

代码说明:

  sliding mode control files for advanced control system

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • rff
    渐消记忆最小二乘法。系统辨识matlab源程序。(fading memory of the least square method. Matlab source system identification.)
    2007-07-02 18:10:13下载
    积分:1
  • D2Q9
    格子LBM计算典型参考,不错的介观计算方法(LBM calculation of the typical reference grid, a good mesoscopic method)
    2010-07-11 22:34:06下载
    积分:1
  • sim_DPSK_passband
    this is a matlab code
    2010-10-24 00:21:26下载
    积分:1
  • 以整数线性规划方法解决火电机组机组组合问题 main
    说明:  以整数线性规划方法解决火电机组机组组合问题。包括爬坡、启停约束等。以最小化运行成本为目标。(Integer linear programming (ILP) is used to solve the unit commitment problem of thermal power units. Including climbing, start-stop constraints and so on. The objective is to minimize operating costs.)
    2020-12-05 21:09:22下载
    积分:1
  • intfilttranspose
    filter based segmentation4
    2011-11-28 17:05:18下载
    积分:1
  • Kalman_Filter
    卡尔曼滤波的源程序,卡尔曼滤波是以最小均方误差为估计的最佳准则,来寻求一套递推估计的算法。(Kalman filtering of source code, Kalman filter based on minimum mean square error for estimating the best criteria to search for a recursive estimation algorithm.)
    2010-12-20 10:35:16下载
    积分:1
  • fft_1
    已知两个序列x[n]=cos(n*pi/2), y[n]=ej*pi*n/4x[n],绘制X(ejw)和Y(ejw)和幅度和相角,说明它们的频移关系(The known two sequence x [n] = cos (n* PI/2), y [n] = ej* PI* n/4 x [n], draw x (ejw) and y (ejw) and amplitude and phase Angle, suggesting their frequency shift relationship )
    2012-04-24 20:17:48下载
    积分:1
  • matchchinese
    本程序实现汉字和字符的识别匹配,通过该算法,可以实现手写体的字符和汉字的识别(This procedure to achieve identification of characters and character matching, through the algorithm, can achieve the character and Chinese character handwriting recognition)
    2009-12-18 14:29:22下载
    积分:1
  • moesp
    A MIMO subspace system Identification method
    2011-07-29 16:31:46下载
    积分:1
  • relay
    mtalab中继节能仿真实现。。。。。。。。。。。。。。。(mtalab relay energy simulation. . . . . . . . . . . . . . .)
    2013-03-09 12:50:10下载
    积分:1
  • 696516资源总数
  • 106409会员总数
  • 8今日下载