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runge
说明: 四阶龙哥库塔方法求解一阶微分方程的数值解法,能自定义迭代步数和迭代精度,非常适合于计算方法的初学者。(Long Ge Kuta fourth-order methods for a numerical solution of differential equations can be customized and iterative iterations precision calculation method is suitable for beginners)
- 2010-04-29 12:26:47下载
- 积分:1
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vof
计算多项流的好程序,简单好用,计算量小。可以较好的模拟二维的两项变化情况(Calculating a number of streams of the program, easy to use, small amount of calculation. Can better simulate the two-dimensional variation)
- 2020-12-01 11:39:27下载
- 积分:1
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linefitransac
ransac直线拟合:使用ransac方法剔除不好的点,留下好的点做直线拟合,这样拟合出的直线更符合实际,因为没有了错误数据的参与。(ransac linear fitting: Use ransac methods eliminate the bad points, making a good point to make fitting a straight line, so that the fitted straight line is more realistic, because there is no involvement of erroneous data.)
- 2016-08-23 20:07:33下载
- 积分:1
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MM1
用C++实现排队论中M/M/1模型。简单方便。(Using C++ implementation in the M/M/1 queuing theory model. Easy and convenient.)
- 2020-11-16 13:39:41下载
- 积分:1
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css
用visual basic编译的布谷鸟算法的源代码,是一种很好地启发式智能算法。(Use visual basic compiler cuckoo algorithm source code, is a good heuristic intelligent algorithm.
)
- 2013-07-19 17:02:51下载
- 积分:1
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matc
matrix inversion source code
- 2012-02-02 18:09:20下载
- 积分:1
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static-condensation
静力缩聚法求缩聚后的结构刚度、质量矩阵,以及频率(Static condensation method for structural stiffness after condensation, mass matrix, and the frequency)
- 2013-07-08 14:38:12下载
- 积分:1
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ADAM
说明: ADAM (Adaptive Moment Estimation)是另外一种自适应学习率算法,它结合动量梯度
下降法,在不同参数方向上采用不同学习率,保留前几次迭代的梯度,能够很好
的适应于稀疏数据。(ADAM (Adaptive Moment Estimation) is another adaptive learning rate algorithm, which combines momentum gradient.
The descent method, which uses different learning rates in different parameter directions and retains the gradients of previous iterations, is very good.
It is suitable for sparse data.)
- 2019-04-09 19:59:50下载
- 积分:1
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MoM
3-D
目标MoM源代码 可以求解球体,旋转体等目标的电磁散射问题(MoM )
- 2020-11-30 20:59:27下载
- 积分:1
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Fundamentals of matrix computations
Fundamentals of matrix computations 矩阵运算的基础(Fundamentals of matrix computations)
- 2017-10-08 14:20:42下载
- 积分:1