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OFDM_SNR_offset
模拟OFDM系统，根据不同的信噪比，测试误码率(Simulated OFDM system, according to different signal to noise ratio, bit error rate test)
- 2010-08-13 12:36:00下载
- 积分：1
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DCT
Compress an decomprres DCT=Domain Transform Coding for image.
- 2009-05-19 21:48:28下载
- 积分：1
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Gradient-Descent
最小梯度下降算法，有测试实例，可以直接运行。求最小值，回归都可以(The minimum gradient descent algorithm, test cases can be run directly. For the minimum, return all OK)
- 2014-10-14 14:05:50下载
- 积分：1
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DCT
this function block an Arbitrary image and take dct from each block.
for check quality of reconstructed image calculated PSNR.
- 2013-08-04 15:18:29下载
- 积分：1
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pcmcode
律u律pcm编码
若输入A律PCM编码器的正弦信号为x(t)=sin(1600πt),采样序列为x(n)=sin(0.2πn),n=0,1,2,…,10，将其进行PCM编码，求出编码器的输出码组序列y(n)。
要求：1) 直接采用A律扩展器函数求解上述问题。
2）使用13折线法近似A律PCM 求解上述问题。
3）计算量化误差。(Law a law pcm coding
If the input A-law PCM encoder is sinusoidal signal x (t) = sin (1600πt), for the sample sequence x (n) = sin (0.2πn), n = 0,1,2, ..., 10, it will be PCM coding to obtain the coded output code group sequence y (n).
Requirements: 1) directly A-law expander function to solve the above problems.
2) using a 13 fold line approximation A-law PCM to solve the above problems.
3) calculating the quantization error.)
- 2016-04-06 19:30:12下载
- 积分：1
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NCO2freqControlWord
NCO频率控制字的计算方法，可以应用在数字中频/基带等众多场景。(The calculation is NCO frequency control word ,which can be used in digital IF/baseband algorithms and many other scenes.)
- 2016-06-27 21:48:37下载
- 积分：1
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mode-propagation-method
说明： 用模式传输法计算多模干涉波导的模场传输,多模干涉波导参数可调(calculate the beam propagation inside MMI using mode propagation method)
- 2010-05-04 17:09:53下载
- 积分：1
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model19th
这是Sorensen等人提出人体血糖-胰岛素模型，依据偏微分方程组搭建的simulink仿真模型。(This simulink model is based on the theory of Sorensen team, which is the blood glucose regulation mechanism of hunman.
)
- 2013-12-05 09:47:50下载
- 积分：1
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hardik
this is scw algorithm to find out the region of interest in given car image to find out license plate
- 2010-02-24 20:27:15下载
- 积分：1
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Chapter3
Hiroshi Harada s Communication System book codes
- 2011-05-08 02:11:10下载
- 积分：1
