-
LMS
最小均方（LMS）自适应算法就是一中已期望响应和滤波输出信号之间误差的均方值最小为准的，依据输入信号在迭代过程中估计梯度矢量，并更新权系数以达到最优的自适应迭代算法。LMS算法是一种梯度最速下降方法，其显著的特点是它的简单性。这算法不需要计算相应的相关函数，也不需要进行矩阵运算。(Minimum mean-square (LMS) adaptive algorithm is that one has to respond to the expectations and filtering the output signal of the mean square error between the value of the minimum-based, based on the input signal is estimated in the iterative process of gradient vector, and to update the weights in order to achieve the most Adaptive iterative algorithm gifted. LMS algorithm is a steepest descent gradient method, and its significant features is its simplicity. This algorithm does not require calculation of the corresponding correlation function, nor the need for matrix calculation.)
- 2008-05-26 12:05:15下载
- 积分：1
-
MATLAB-ZUO-TU-GONG-NENG
讲述了MATLAB的图形的画法，对初学者和编程序想要产生对比图形的很有帮助(This PPT tell the way of drawing a picture in matlab)
- 2013-07-24 09:26:14下载
- 积分：1
-
空间机械臂力与位置协调控制
空间机械臂动力学建模，力与位置协调控制，并用了pid控制算法仿真，(pace manipulator, direct path method, Lagrangian formulation, hybrid force/position control)
- 2020-06-29 20:40:02下载
- 积分：1
-
msx60_model
Ce fichier mdl permet de tracer la caractéristique pv
- 2013-01-02 22:22:08下载
- 积分：1
-
UL_SRS
LTE频分双工模式下的上行信道探测的MATLAB代码，实现上行信道的探测。(The SRS matlab code of the up_link of FDD-LTE .)
- 2012-08-23 18:38:23下载
- 积分：1
-
matlab_FEM_dismesh
DistMesh giving a singular FEM matrix?(Hi
Anyone here with some experience of using DistMesh in finite element code? I m solving the scalar Helmoltz equation in an annular region in 2D:
rho_1 < rho < rho_2
where rho_1 is the radius of a Perfect Electric Conducting cylinder and rho_2 is where the mesh is truncated using an Absorbing Boundary condition.
Now, I ve written code to mesh the region myself (by dividing the region into annular rings and picking a fixed number of points on each ring) and I ve written another program which uses DistMesh to mesh the region. I get a nice solution using my own meshing code but the FEM matrix becomes singular when I use DistMesh. This is the DistMesh Code I used:
Circle with hole
rABC=1.5
rCyl=0.5
fdstring=sprintf( ddiff(dcircle(p,0,0, f),dcircle(p,0,0, f)) ,rABC,rCyl)
fd=inline(fdstring, p )
box=[-2,-2 2,2]
[p,N]=distmesh2d(fd,@huniform,0.04,box,[])
I tried changing box and the 0.04 value (initial edge length). But every time, the matrix becomes sin)
- 2010-06-05 09:17:55下载
- 积分：1
-
matlab_book
这是一个关于matlab的电子书，适合初学者，讲解matlab基础知识，simulink，notebook等，是一本比较全面的书籍，有部分程序(This is a matlab about the e-books, suitable for beginners, basic knowledge of matlab on, simulink, notebook and so on, are a more comprehensive books, has some of the procedures)
- 2009-03-23 10:43:03下载
- 积分：1
-
ST4
独立分量分析之四阶距方法的程序，采用matlab编写(Independent component analysis of four bands from the methods of procedure for the preparation of matlab)
- 2009-04-07 10:46:00下载
- 积分：1
-
mm
说明： 旅行商问题( TSP) 的改进模拟退火算法(Traveling Salesman Problem (TSP) to improve the simulated annealing algorithm)
- 2009-08-18 16:52:32下载
- 积分：1
-
fdtd3D_UPML
help me to help another
- 2011-04-29 02:55:14下载
- 积分：1
