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ex_menu
MATLAB 7.0编程基础基础源程序 相当好(based programming source very good foundation)
- 2006-09-26 16:53:08下载
- 积分：1
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matlab1
控制工具箱与SIMULINK软件应用：系统对象为G(s)=4/s(s+2)
PI补偿器K1(s)=(s+1)/s K2(s)=(s+0.5)/s
a 若由K1(s)与 G(s)串联组成的单位反馈系统，称为系统A。
b 若由K1(s) 放置在G(s)的反馈通道称为系统B。
c 若由K2(s)与G(s)串联组成的单位称为系统C，绘制上述每一种情况的阶跃响应与斜坡响应，求每一种情况下的系统阶跃响应误差与斜坡响应误差，并与理论分析结果进行比较。
(Control toolbox and SIMULINK software application: system object for G (s) = 4/s (s+ 2)
PI compensator K1 (s) = (s+ 1)/s K2 (s) = (s+ 0.5)/s
If a by K1 (s) and G (s) series of feedback system of the unit, known as a system a.
B if the K1 (s) placed in G (s) feedback channel called system b.
If c by K2 (s) and G (s) series of unit is called system c, draw the above each kind of condition of step response and slope response, for each of these cases system step response error and slope response error, and the results were compared with theoretical analysis.)
- 2012-04-19 14:43:49下载
- 积分：1
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liver
result of filtering in audio processing
- 2014-12-14 04:20:32下载
- 积分：1
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erzhihua201504102
图像的二值化,不使用Matlab自带的语句处理，使用的是自己的编程语句。(Binary image, do not use Matlab s own statement processing, using their own programming statements.)
- 2015-04-20 16:35:24下载
- 积分：1
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LTE_System_Level_1.4_r570
To solve this instance of the decision problem we must determine whether there is a truth value (TRUE or FALSE) we can assign to each of the variables (x1 through x4) such that the entire expression is TRUE. In this instance, there is such an assignment (x1 = TRUE,x2 = TRUE, x3=TRUE, x4=TRUE), so the answer to this instance is YES. This is one of many possible assignments, with for instance, any set of assignments including x1 = TRUE being sufficient. If there were no such assignment(s), the answer would be NO.
- 2012-04-23 22:00:12下载
- 积分：1
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eigen-induction-motor.m.txt
Induction motor eigen control
- 2013-12-17 04:25:33下载
- 积分：1
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two
数字图象水印的嵌入及提取,MATLAB源程序,初学者的水平(Digital image watermark embedding and extraction, MATLAB source code, beginner level)
- 2008-02-28 15:21:11下载
- 积分：1
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matlab
文件1：复数的表达与计算；文件2：用matlab计算∛ (-8)，并用图形表示；文件3：用符号计算研究方程sin(3)uz^2+vz+3w-a5=0的解；文件4：求阿基米德螺线r=a*θ,(a>0)在θ=0到φ间的曲线长度函数，并求a=1,φ=2п间的曲线长度；文件五：著名的Givens旋转G=[■(cos t&-sin t@sin t&cos t)]对矩阵A=[■(√3/2&1/2@1/2&√3/2)]的旋转作用。(five programs about matlab)
- 2012-03-29 23:41:50下载
- 积分：1
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25856376
Fox Hunting Algorithm
- 2019-02-27 18:35:06下载
- 积分：1
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LevelSetMethods
Level Set Based Image Segmentation
- 2010-11-02 06:28:40下载
- 积分：1
