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power_statcom_gto48p_22_6

于 2011-06-23 发布 文件大小:40KB
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下载积分: 1 下载次数: 8

代码说明:

  48 pulose gto trial for new project based on matlab

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  • F_JIDtjl
    可以进行相似矩阵的建立 很不错的一款程序 运算数独很快(Similar matrix can be established very good procedures for computing a fast Sudoku)
    2011-08-17 00:58:55下载
    积分:1
  • gaph
    本程序需要用到MATLAB遗传算法工具箱,但是遗传算法工具箱有很多种,这里使用GEATbx工具箱,该工具箱是由英国Sheffield大学开发。(This program requires MATLAB genetic algorithm toolbox, but there are many genetic algorithm toolbox used here GEATbx toolkit, which was developed by the University of Sheffield, UK.)
    2013-12-17 15:53:19下载
    积分:1
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    2013-12-10 09:56:50下载
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    2013-05-09 04:17:58下载
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  • maichongyasuo
    说明:  该代码主要实现matlab中脉冲压缩的仿真算法,主要用于初学者进行初步学习。(This code mainly realizes the simulation algorithm of pulse compression in MATLAB, which is mainly used for beginners to carry out preliminary learning.)
    2020-04-05 13:27:55下载
    积分:1
  • circsine
    generates circular sine wave grating
    2010-10-15 19:05:18下载
    积分:1
  • RGB2YUV222
    该程序实现了彩色图像到RGB以及YUV分量的转化,思路清晰,可直接运行。(The program implements the image to RGB and YUV color component transformation, clear, can be directly run.)
    2010-05-26 21:20:07下载
    积分:1
  • matlab_queue_system
    自己写的用Matlab模拟一个缓冲区大小(包括正在服务的那个)为10的随机排队系统。 (1)到达过程是的泊松过程(到达速率为Mu),服务时间服从独立指数分布(均值为1/Lamda)。 对Mu//Lamda=0.2,Mu//Lamda=0.8和Mu//Lamda=1.1三种情况进行仿真,求出队列中接受服务用户为n的概率P(n), n=0,...,10。并与理论结果进行比较。 (2)假设到达过程为均匀过程(到达速率为Mu),服务时间服从独立瑞利分布(均值为1/Lamda)。(yourself writing a simulation using Matlab buffer size (including services that are) for the following 10 Machine queuing system. (1) arrival process is the Poisson process (arrival rate of Mu), submit to independent service index distribution (mean of 1/Lamda). Right Mu// Lamda = 0.2, Mu// Lamda = 0.8 and the Mu// = 1.1 Lamda three of the simulation, Queue calculated users receive services n the probability P (n), n = 0 ,..., 10. And with the theoretical results. (2) It is assumed that the arrival process for the uniform process (arrival rate of Mu), submit to independent service Rayleigh distribution (mean of 1/Lamda).)
    2007-05-16 09:14:40下载
    积分:1
  • work
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