-
stack
数据结构 堆栈 实现了以下功能:
cout<<"----------------主菜单---------------"<<endl
<<"* 1.建立 *"<<endl
<<"* 2.输出 *"<<endl
<<"* 3.判断栈是否为空 *"<<endl
<<"* 4.栈的长度 *"<<endl
<<"* 5.输出栈顶元素 *"<<endl
<<"* 6.进栈 *"<<endl
<<"* 7.出栈 *"<<endl
<<"* 8.遍历 *"<<endl
<<"* 9.数制转换 *"<<endl
<<"* 10.清空 *"<<endl
<<"* 11.销毁 *"<<endl
<<"* 12.退出 *"<<endl
<<"--------------------------------------"<<endl<<endl (data structure stack)
- 2013-11-01 11:05:10下载
- 积分:1
-
基于单链表的多项式的运算
实现已下功能:
1.创建有头结点的单链表存储多项式的指数和系数。
2.输出多项式。
3.多项式的相加。
4.多项式的相乘。
- 2022-02-21 12:48:52下载
- 积分:1
-
pinfanfangwen
设有一头指针为L的带有表头结点的非循环双向链表,其每个结点中除有prev(前驱指针),data(数据)和next(后继指针)域外,还有一个访问频度域freq。在链表被起用前,其值均初始化为零。每当在链表中进行一次Locate(L,x)运算时,令元素值为x的结点中freq域的值增1,并使此链表中结点保持按访问频度非增(递减)的顺序排列,同时最近访问的结点排在频度相同的结点的最后,以便使频繁访问的结点总是靠近表头。试编写符合上述要求的Locate(L,x)运算的算法,该运算为函数过程,返回找到结点的地址,类型为指针型。(Has a head pointer is non-circular doubly linked list L with a header node, each node in addition to prev (precursor pointer), data (data) and next (successor pointers) outside, there is an access frequency degree domain freq. Before the list was hired, their values are initialized to zero. Whenever carried out in the list once Locate (L, x) when the operation, so that the element node x is the value in freq domain by one, and keep this list in the node-access frequency of non-increasing (decreasing) the order, while a recent visit to the nodes in the same row of the frequency of the last node, so that the nodes are frequently accessed tables are always near the head. Locate (L, x) algorithm is prepared in accordance with the above requirements of the test operation, the operation as a function of the process, return to find the address of the node of type pointer.)
- 2015-01-15 22:31:59下载
- 积分:1
-
VB学生成绩管理系统,使整套日…
VB student result management system management system, brings the entire wrap the paper, has the very high reference value to the graduation project.
- 2022-04-18 08:23:40下载
- 积分:1
-
编程实现出圈问题。是上《数据结构》时候的一次实习的成果。...
编程实现出圈问题。是上《数据结构》时候的一次实习的成果。-Programming problem to achieve a circle. It s a program produced during learning data structure
- 2022-03-11 09:00:17下载
- 积分:1
-
从ACCESS文件中提取DBF文件,可以将ACCESS文件中提取DBF文件,并建立一个数据库文件,包括ACCESS文件中的所有表....
从ACCESS文件中提取DBF文件,可以将ACCESS文件中提取DBF文件,并建立一个数据库文件,包括ACCESS文件中的所有表.-ACCESS documents from the DBF file extraction can be extracted ACCESS DBF file documents, and the establishment of a database file, including documents, the ACCESS all the tables.
- 2022-02-22 12:36:12下载
- 积分:1
-
on data structures and algorithms is the teacher's curriculum courseware all...
这是我上数据结构和算法课程是老师的课件 所有算法都用c++实现拉 .比用伪代码描叙要 好得多-on data structures and algorithms is the teacher"s curriculum courseware all algorithms are used to achieve c Rafah. Pseudo code than depicts much better
- 2022-05-18 01:14:35下载
- 积分:1
-
数据库查询示例程序 数据库查询示例程序
数据库查询示例程序 数据库查询示例程序 -Procedures database query database query examples of sample programs
- 2022-03-11 05:42:04下载
- 积分:1
-
Data structure to solve the problem in the maze, the maze problem. Vcproj This i...
数据结构中迷宫问题的求解,迷宫问题.vcproj
这是使用应用程序向导生成的 VC++ 项目的主项目文件。
它包含生成该文件的 Visual C++ 的版本信息,以及有关使用应用程序向导选择的平台、配置和项目功能的信息。
迷宫问题.cpp
这是主应用程序源文件。
StdAfx.h, StdAfx.cpp
这些文件用于生成名为 迷宫问题.pch 的预编译头 (PCH) 文件和名为 StdAfx.obj 的预编译类型文件。
-Data structure to solve the problem in the maze, the maze problem. Vcproj This is using an application wizard to generate the VC++ project the main project document. It contains the document to generate Visual C++ version information, as well as applications relating to the use of the wizard select the platform, configuration and project features. Maze problem. Cpp This is the main application source file. StdAfx.h, StdAfx.cpp these files used to generate a maze called the question. Pch precompiled header (PCH) files and named StdAfx.obj type of pre-compiled files.
- 2022-06-21 21:34:29下载
- 积分:1
-
使用sqlite3进行存取图片二进制数据
前段时间在做一款嵌入式项目,用到了SQLite数据库,现在就SQLite数据库中存取图片问题来与大家共享一下,对于二进制数据我们自然是不能够直接进行存储,在SQLite中我们可以将其转换而后存储。
在对主句操作之前我们先要打开数据库,SQLite给用户提供了丰富的API,足以使我们来驾驭它,利用sqlite3_open()函数,打开我们所要操作的数据库,接下来就是对于我们的图片文件的操作了,我在这里的方法便是将图片文件转换成字符流,而后进行存储。
- 2023-03-25 20:45:05下载
- 积分:1