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TRIAC
测量跟踪探测的一段MATLAB代码说明
TRIAC II. A MatLab code for track measurements from SSNT detectors(Measurement to detect the section of track MATLAB Code Description TRIAC II. A MatLab code for track measurements from SSNT detectors)
- 2007-12-20 04:54:52下载
- 积分：1
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SVM_luzhenbo
用于分类的matlab工具箱，供大家学习交流(Matlab toolbox for classification ，We can exchange advices with it.)
- 2009-04-07 22:19:42下载
- 积分：1
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army
用16C62写的汽车防盗器程序，自动防盗，锁定汽车的油路电路(with 16C62 written procedures for vehicle anti-theft device, automatic anti-theft, motor vehicle lock on the asphalt circuit)
- 2007-03-29 23:15:57下载
- 积分：1
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Matlab-Recips
Matlab Recips for Earth Sciences--2nd Edition
- 2013-12-25 16:15:51下载
- 积分：1
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PhysicalModelinginMATLAB
Most books that use MATLAB are aimed at readers who know how to program.
This book is for people who have never programmed before.
- 2009-10-04 01:59:48下载
- 积分：1
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tongxin_matlab
现代通信系统分析与仿真：MATLAB通信工具箱(Modern communication systems analysis and simulation: MATLAB Communications Toolbox)
- 2008-04-18 16:13:32下载
- 积分：1
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tiaopin
说明： 调频信号的时-频分析 针对时变信号有很好的效果(When FM signals- frequency analysis for time-varying signal has good results)
- 2007-10-11 20:36:36下载
- 积分：1
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MUSIC-CAPON
仿真分析：基于MUSIC算法和CAPON算法的仿真，给出了仿真图与仿真结果(Simulation Analysis: CAPON algorithm based on MUSIC algorithm and the simulation, the simulation diagram and simulation results)
- 2010-11-07 19:52:50下载
- 积分：1
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MATLAB_2
说明： 本書完整的說明與充分的網路支援，可以使讀者能充分地掌握MATLAB的脈動，擁有解決工程問題的最佳利器,11-20章(A complete description of the book and the full network support, will enable readers to fully grasp the pulse of MATLAB, has to solve engineering problems in the best weapon, 11-chapter 20)
- 2008-08-26 21:07:08下载
- 积分：1
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111
function pi = solve2(count,m,cc)
借助布冯投针实验 仿真求pi的值
pi=0
frq=0
randNo = binornd(1,cc,1,m)
pro=zeros(1,count)
for j=1:count
for i = 1:m
if randNo(1,i) == 1
frq = frq + 1
end
pro(i) = frq/i
end
pi = (2*m)/frq
pro(j) = pi
end
pro = pro,num =1:count
plot(num,pro) (function pi = solve2 (count, m, cc) to vote with Buffon needle experiment simulation find the value of pi pi = 0 frq = 0 randNo = binornd (1, cc, 1, m) pro = zeros (1, count) for j = 1: count for i = 1: m if randNo (1, i) == 1 frq = frq+ 1 end pro (i) = frq/i end pi = (2* m )/frq pro (j) = pi end pro = pro, num = 1: count plot (num, pro) )
- 2011-05-24 15:39:41下载
- 积分：1
