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PSOmatlabscource
说明： 详细讲解粒子群算法并附带有粒子群算法源码程序！相信对你一定有用！(Explained in detail along with the PSO PSO source programs! I believe you must be useful!)
- 2011-03-07 21:19:06下载
- 积分：1
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PSK8
说明： 关于8PSK解的信噪比和调误码率的仿真程序(8PSK solution on the signal to noise ratio and bit error rate of transfer simulation program)
- 2008-10-18 09:39:19下载
- 积分：1
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m-files
Use prec=0.01 or prec=0.005 for larger image
with better resolution (and longer runtime...)
- 2014-12-19 08:56:57下载
- 积分：1
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project
对双极性随机序列二进制数字基带信号，采用开方升余弦滚降波形、矩形脉冲、半波正弦在白噪声条件下的最优（匹配滤波器）接收程序。考察码间串扰和白噪声共同作用引发的误码，画出误码率曲线；设计均衡器画出误码率曲线。(Bipolar random sequence of binary digital baseband signal, using the square root raised cosine wave, rectangular pulse, half sine wave white noise under optimal conditions (matched filter) receiver. Crosstalk and white noise error caused by interaction between the inspection code, drawn BER curves design equalizer to draw BER curves.)
- 2014-12-28 20:01:30下载
- 积分：1
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ecg_analysis
In this paper, a new approach in human identification
is investigated. For this purpose, a standard 12-lead electrocardiogram
(ECG) recorded during rest is used. Selected features
extracted from the ECG are used to identify a person in a predetermined
group. Multivariate analysis is used for the identification
task.
- 2010-09-05 13:52:31下载
- 积分：1
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Downloads
两段强化学习算法，提供给研究算法的同学。不知道有没有用(The two reinforcement learning algorithms, to provide students to study algorithm. Do not know that there is no use)
- 2012-04-04 16:16:52下载
- 积分：1
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lssvm_Mfilter21_MSC_100
原始数据存储为excell文件，先将数据进行预处理，再通过SVM进行模型的建立与预测。(The data are stored as a excell file, preprocessing the original data and builting the SVM model.)
- 2012-05-10 09:28:38下载
- 积分：1
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filwe1_11
线性调频信号产生
带宽为240MHz
脉冲宽度为5us(Chirp signal bandwidth of 240MHz generate a pulse width of 5us)
- 2013-11-02 17:16:40下载
- 积分：1
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we
说明： 七单元天线阵DOA估计
clear clc
d=1 天线阵元的间距
lma=2 信号中心波长
q1=1*pi/4 q2=1*pi/3 q3=1*pi/6 q4=3*pi/4 四输入信号的方向
A1=[exp(-2*pi*j*d*[0:6]*cos(q1)/lma)] 求阵因子
A2=[exp(-2*pi*j*d*[0:6]*cos(q2)/lma)]
A3=[exp(-2*pi*j*d*[0:6]*cos(q3)/lma)]
A4=[exp(-2*pi*j*d*[0:6]*cos(q4)/lma)]
A=[A1,A2,A3,A4] 得出A矩阵
n=1:1900
v1=.015 四信号的频率
v2=.05
v3=.02
v4=.035
d=[1.3*cos(v1*n) 1*sin(v2(we)
- 2010-05-06 15:26:50下载
- 积分：1
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MUSIC
基于MUSIC的DOA估计，算法简单较为快捷可以修改(easimation of DOA)
- 2012-11-04 17:07:49下载
- 积分：1
