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hf
说明： Hartree fock in quantum
- 2010-07-08 14:52:31下载
- 积分：1
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RAFisher2cda
Canonical Discriminant Analysis is a dimension-reduction technique related to PCA and CCA
- 2009-12-21 18:43:08下载
- 积分：1
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otimization-problem
This algorithm solves the otimization problem
min_x | y - A x |_2^2 + lambda Phi(x)
and has applications in compressed sensing, image restoration
and reconstruction, sparse regression, and several other problems.
- 2020-11-22 22:29:35下载
- 积分：1
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ECGstroop.mat
ECG on stroop test taken on 250 Hz (sampling frequency) You can use in order to obtain (and compare) the stress (from HRV)
- 2013-08-22 00:31:19下载
- 积分：1
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13.USING-ACTIVE-POWER-FILTERS-TO-IMPROVE-POWER
This paper describes different power quality
problems in distribution systems and their solutions with
power electronics based equipment. Shunt, hybrid and
series active power filters are described showing their
compensation characteristics and principles of operation.
Different power circuits topologies and control scheme for
each type of active power filter are analyzed. The
compensation characteristics of each topology with the
respective control scheme are proved by simulation and
experimentally.
- 2014-10-09 01:20:59下载
- 积分：1
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PSO_MATLAB_toos
matlab的PSO工具箱，只需对参数和目标函数设定就可以进行粒子群计算(PSO toolbox matlab, simply set the parameters and the objective function can be particle swarm meter
)
- 2012-02-06 19:29:15下载
- 积分：1
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3
说明： 本程序用pca，kpca,svm,pls,fisher，贝叶斯实现cstr和csth过程的故障检诊断，诊断率为百分之九十九，故障识别率为百分之五十八(The program use pca, kpca, SVM, PLS, fisher, bayesian realize CSTR and CSTH process for diagnosis fault diagnosis rate is ninety-nine percent, and the fault recognition rate is fifty-eight percent)
- 2012-02-29 09:50:09下载
- 积分：1
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watermarker_source_demo
about watermarking for images and text
- 2009-02-23 14:54:08下载
- 积分：1
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AES
code for AES to to encrypt data
- 2013-02-02 19:09:22下载
- 积分：1
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2DMaxima
在二维空间里有两个点A=(X1，Y1)和B=(X2，Y2)，如果X1>X2并且Y1>Y2 ，我们认为A优于B，A是这个集合的最大极值点，在给定的二维空间里的N个点的集合S中，找出最大极值点。(In two-dimensional space, there are two points = A = (X1, Y1) and B (X2, Y2), if the X1 and Y1 > X2 > Y2, we think that A is superior to B, A is the biggest extreme value point of the set, in A given set of N points in the two-dimensional space S, find out the most extreme value point.)
- 2013-12-24 21:02:56下载
- 积分：1
