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pendulummodelandswingup
说明： 详细介绍了单级倒立摆模型的建立，稳定控制和起摆控制的仿真及实时控制的实现，二级摆和三级摆的控制(Details of the single-stage model of inverted pendulum, stability control and swing control of the simulation and realization of real-time control, secondary and tertiary pendulum swing)
- 2011-03-08 15:20:45下载
- 积分：1
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boost1
invetre 3phase by jahed
- 2011-05-27 20:50:13下载
- 积分：1
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chaoliu
本程序是基于matlab编程的牛顿拉夫逊法潮流计算程序(The program is based on matlab Newton Ralph Gibson flow calculation method program)
- 2012-05-09 20:32:36下载
- 积分：1
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gas_diffusive
污染物扩散的数值模拟，单扩散，无源，对热传递很有帮助(Pollutant dispersion simulation, single diffusion, passive, very useful for heat transfer)
- 2011-07-04 21:43:54下载
- 积分：1
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postp1D_appe
非常不错的小波程序(very good wavelet procedures!)
- 2007-05-30 11:10:38下载
- 积分：1
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Queens
本程序用Matlab实现了八皇后问题的所有解，用到了递归的编程思想(The procedures used Matlab eight queens problem all the solutions use recursive programming ideas)
- 2013-03-16 23:46:42下载
- 积分：1
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vedio_skin_face_detecting
自带摄像头基于肤色的人脸检测，可实现跟踪功能。(face detection)
- 2015-03-26 16:29:39下载
- 积分：1
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DSSS
扩频系统的MATLAB源代码,实现无线通信系统扩频的功能(spread spectrum systems MATLAB source code, wireless spread-spectrum communication system function)
- 2006-05-23 16:33:17下载
- 积分：1
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MATLAB
介绍MATLAB的ppt课件，有助于在短时间里学会运用MATLAB。对数学建模很有帮助。(Introduction MATLAB-ppt courseware, helping in a short time learn to use MATLAB. Useful for mathematical modeling.)
- 2009-09-06 13:39:25下载
- 积分：1
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Chapter6
数值解法
例1 用改进的欧拉方法求一阶方程初值问题的
数值解
例2 数学摆的运动方程与近似方程数值解比较
例3 四阶龙格库塔公式求数值解
Matlab实现求数值解
例1 求初值问题y =x*sin(x)-y,y(0)=0的数值
解.先编辑一个定义方程的ODEF函数文件
ODEfun1.m.
例2 求方程组初值问题的数值解,按指定步长
0.05划分节点.
例3 按指定的精度求高阶方程初值问题的数值解.(Numerical Solution of the law a method of using the improved Euler' s equation of order to a first-order initial value problem of the numerical solution of cases of two mathematical pendulum equations of motion compared with the approximate numerical solutions of equations of three cases of fourth-order Runge-Kutta numerical solution of the formula Matlab order to achieve the numerical solution of demand cases seeking an initial value problem y ' = x* sin (x)-y, y (0) = 0 the numerical solution. first, the definition of an equation editor ODEF function file ODEfun1.m. cases of two demand equations initial value problem of numerical solution, according to the specified division of the node step 0.05. Example 3 according to the specified precision of seeking higher-order equation of the numerical solution of initial value problem.)
- 2010-02-05 23:14:41下载
- 积分：1
