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chap11
说明： 本目录主要包括：文档和两个源代码。
其中一个源代码是识别程序的，另一个是一个矩阵类库的，书里面也使用过，所以一并附上。
因为已经保存了训练好的网络权值，所以第一次使用识别程序时，可以直接运行\\Release目录下的可执行文件，然后对图片目录中的测试图片进行读入、识别。
当然读者也可以自行用训练样本训练网络，不过要特别注意训练样本的选择，否则可能造成识别率很低。训练样本选择的原则是，尽可能的有代表性，在训练时间不至于太长的情况下，训练样本数目尽量多。
( This directory includes: documentation and two source code.
One of the source code is to identify the procedure, the other is a matrix class library, the book which is also used, so be attached.
Because it has saved the trained network weights, so the first use of identification procedures, you can directly run \ \ Release directory of the executable files, and then tested on the images directory to read pictures, identification.
Of course, readers are free to use the training samples to train the network, but pay special attention to training samples, otherwise it may cause very low recognition rate. Training sample selection principle is that as far as possible, representative, in the long training time Buzhi Yu s case, the number of training samples as much as possible.
)
- 2010-04-11 22:26:09下载
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Smith
smith chart用于微波和电磁波分析和计算，在通讯工程中有良好的应用。(smith chart used for analysis and calculation of microwave and electromagnetic waves in communication engineering has a good application.)
- 2011-05-26 20:45:07下载
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PSO_MATLAB
这段代码实现的是基于MATLAB的MIMO-OFDM的系统多用户检测，采用的算法是粒子群优化算法，他能提高系统的性能(This code implementation is based on the MATLAB MIMO- OFDM system, multi-user detection is the particle swarm optimization algorithm, the algorithm used he can improve the performance of the system)
- 2015-04-21 11:33:13下载
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5
一道程序编译顺序的考题，涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。
C的程序编译总是从main函数开始的，这道题的重点在“fun（（int）fun（a+c,b）,a-c）） ”语句。
系统首先要确定最外层 fun()函数的实参，第一个参数的确定需要递归调用fun()函数（不妨称其为内层函数）。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)
- 2009-03-15 15:36:23下载
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Untitled2
this is asimple matlab file....
- 2010-05-18 01:39:16下载
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ncm
matlab里面的一些简化工具包，便携易带，ncm工具包，还有一些教学演示程序(the matlab toolbox simple!please,if you want to show something,you can use it)
- 2012-05-16 17:06:10下载
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mv
说明： machine vision 工具箱，一直都在用，做机器视觉参考(machine vision toolkit has been used, so machine vision reference)
- 2007-04-19 17:07:19下载
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Main
Numerical solution of wave equation using three methods, 1)Upwind 2)Leap-Frog 3)Maccormack.
- 2014-11-19 15:33:04下载
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CtrlLAB
工具箱，控制理论发展的最新成果，很好的东西，分分享(Toolbox, the latest development of control theory, very good, sub-share)
- 2010-07-25 16:39:44下载
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SIMUL_LDPC
simulink for Low-density parity-check code
- 2010-05-24 00:22:13下载
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