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libsvm_3_select_cu_regression
本程序是对粮虫的3类回归的具体实现中的C和g的参数优化选择程序(This procedure is a Class 3 grain insects in the concrete realization of the return of C and g the parameter optimization selection process)
- 2011-05-11 00:21:17下载
- 积分：1
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mouth
人脸识别，嘴部提取。人脸识别，嘴部提取。人脸识别，嘴部提取。(face mouth extraction
face mouth extraction
face mouth extraction)
- 2015-04-26 10:36:57下载
- 积分：1
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Program
使用了遗传算法对从仓库到各个客户点的车辆运输方案进行优化，得到一个可行的结果(The genetic algorithm is used to optimize the vehicle transport scheme the warehouse to the customers, and get a feasible result.)
- 2015-06-09 12:48:09下载
- 积分：1
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zishiyingxindaojunhengqi
使用下面的参数设计信道均衡器，其中使用两个独立的随机数发生器，一个用x(n)来表示，用来测试信道；另一个用v(n)来表示，用来模拟接收器中的加性白噪声的影响。序列x(n)是x(n)=±1的伯努利序列，随机变量x(n)具有零均值和单位方差。第二个序列v(n)具有零均值，其方差由信噪比决定。均衡器有11个抽头。(Use the following parameter design of channel equalizer, which uses two separate random number generator, one with x (n) to indicate, to test the channel the other with v (n) to indicate to simulate the receiver in The additive white noise. Sequence x (n) is x (n) = ± 1 of the Bernoulli sequence of random variable x (n) with zero mean and unit variance. The second sequence v (n) has zero mean, its variance decision by the signal to noise ratio. There are 11-tap equalizer.)
- 2010-01-13 18:33:25下载
- 积分：1
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shipinxinhaofenbu
利用matlab对信号进行时频分析,信号重排处理,不妨看一看(using Matlab to signal time-frequency analysis, signal processing rearrangement, we might look at the)
- 2007-06-26 11:24:43下载
- 积分：1
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mrc_ber
Bit error rate of MRC
- 2013-09-19 20:29:32下载
- 积分：1
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YTY_GA_Final
To find the largest fitness value and its location
寻找最大适应性及相应的位置！ Population N=50；crossover bits=n/2 (half of bits of an individual) with random locations，mutation bits = 4 种群数 N=50，交换位数= n/2, 即个体位数的一半，且位置随机；
变异位数统一取为4；
Nc=20，28，36，44，individuals for crossover(交换的个数)。 Nm=1，5，10，15， individuals for mutation(变异的个数)。 (To find the largest fitness value and its location to find the location of the maximum adaptability and the corresponding! Population N = 50 crossover bits = n/2 (half of bits of an individual) with random locations, mutation bits = 4 population size N = 50, exchange digits = n/2, ie half of the median individual, and random position variation is taken as unity median 4 Nc = 20,28,36,44, individuals for crossover (exchange number). Nm = 1,5,10,15, individuals for mutation (the number of variations.))
- 2010-12-27 21:23:27下载
- 积分：1
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hilbert
so what should i write, im tired of writting
- 2011-06-13 16:16:49下载
- 积分：1
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遗传算法下的经济调度
微电网的经济调度，MATLAB编写，含数据(Microgrid economic dispatch, MATLAB compilation, including data)
- 2020-11-03 09:29:53下载
- 积分：1
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driffill_code
muller法, 可以對方程式求數值解 muller method and newton method(muller method)
- 2010-10-29 07:32:48下载
- 积分：1
