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cookies-baidufatie
利用cookies控制的百度发帖机源代码。很久之前做的。大家可以参考一下(The control of the use of cookies Baidu posted machine source code. Long ago to do. We can refer to)
- 2009-11-07 20:33:51下载
- 积分：1
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linear_DBF
线阵的两种数字波束形成的MATLAB程序，固定权值的，添加了汉明窗以抑制旁瓣。(Linear array of two kinds of digital beamforming in MATLAB program, a fixed weight, and added a Hamming window to suppress sidelobe.)
- 2009-11-15 20:22:32下载
- 积分：1
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prgm
matlab programs used to calculate conv,autocorrelation,dft,
idft,etc
- 2011-01-19 15:31:30下载
- 积分：1
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zhendong
说明： 振动的模拟的matlab源程序，来源于网络,
谢谢大家！(vibration source Matlab simulation, and from the network, thank you all!)
- 2006-03-18 19:57:46下载
- 积分：1
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FSK-Modulation
FSK modulation and FSK demodulation
- 2012-06-08 20:43:29下载
- 积分：1
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p-0758--Telephone-Billing-System
good projet for bbeginners ey useful
- 2013-11-05 10:43:30下载
- 积分：1
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Desktop
牛顿法进行二次曲面分析，计算各迭代点的局部值(Newton s method analysis of quadric surface, the local value of iterative point is calculated)
- 2013-12-28 11:15:51下载
- 积分：1
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RRT-star-master
RT（快速扩展随机树）是一种基于采样的算法求解路径规划问题。RRT提供可行的解如果时间RRT趋于无穷大。
RRT *是一个基于采样的算法为解决运动规划问题，这是一个概率最优变异性。RRT *收敛到最优解的渐近。
RRT * FN是一个基于采样的算法基于RRT *。RRT * FN内在渐近收敛到最优解，然而RRT * FN实现使用更少的内存(RRT (Rapidly-Exploring Random Tree) is a sampling-based algorithm for solving path planning problem. RRT provides feasable solution if time of RRT tends to infinity.
RRT* is a sampling-based algorithm for solving motion planning problem, which is an probabilistically optimal variant of RRT. RRT* converges to the optimal solution asymptotically.
RRT*FN is a sampling-based algorithm based on RRT*. RRT*FN inherents asymptotical convergence to the optimal solution, however RRT*FN implements it using less memory.)
- 2017-07-21 11:05:22下载
- 积分：1
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MATLABNewtonRaphson
用matlab编的朝里计算 牛顿拉夫逊直接坐标 解潮流(Matlab compiled by North Korea in the calculation of Newton Raphson solution directly coordinates the trend)
- 2010-10-23 19:00:52下载
- 积分：1
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GAOT_BY_SheffieldUniv
英国谢菲尔德大学推出的GA算法工具箱，只能说，很好，很强大(GA toolbox by Sheffield Univ, excellent and perfect.)
- 2010-07-18 16:36:35下载
- 积分：1
