CLOCK

代码说明：

  钟面上的时针和分针之间的夹角总是在 0 ～180之间 ( 包括 0 和180 ) 。举例来说，在十二点的时候两针之间的夹角为 0 ，而在六点的时候夹角为180 ，在三点的时候为90 。本题要解决的是计算 12:00 到 11:59 之间任意一个时间的夹角。(The angle between the hour and minute hands of the clock face is always between 0 to 180 (including 0 and 180). For example, twelve o' clock, when the angle between the two pin 0, in the six o' clock when the angle is 180, three points for 90. This question must be resolved are the angle of the calculation of 12:00 to 11:59 any one time.)