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ART2C++
该算法是常用的ART2的vc++实现算法，代码思路清晰，注释详细，相信对ART2网络的初学者有很大帮助。(The ART2 algorithm is commonly used in the vc++ Realization of algorithms, code clear, detailed notes, I believe ART2 networks are very helpful for beginners.)
- 2008-12-15 17:39:08下载
- 积分：1
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基于中国剩余定理的秘密共享方案
演示门限密码方案基本原理，使用miracl库(Demonstrate the basic principle of threshold cryptography scheme, using miracl Library)
- 2020-12-14 16:09:14下载
- 积分：1
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8df5833b7339
win32 SDK 方式实现拦截系统关机(Win32 SDK)
- 2013-09-16 14:11:26下载
- 积分：1
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LuaPlus_Test
Lua测试工具源码，自己写的东西。希望能有点用处。(Lua source code testing tools, their own writing. Hope to be of some use.)
- 2010-06-05 19:16:30下载
- 积分：1
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SSHClient
Windows系统下，SSH加密机制，用户身份认证代码，主要用于检测用户弱口令。(Windows OS，SSH encrypt，check the user s password on line.)
- 2013-11-12 17:01:31下载
- 积分：1
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moshishibiesuanfashiyanshuju
该数据集中的数据是由鸢尾属植物的三种花——Setosa、Versicolor与Virginica——的测量结果所组成，数据集中共包含150组数据信息，每一类别植物有50组数据。( The data in the dataset is composed of three species of Iris flowers- Setosa, Versicolor and Virginica- consisting of the measurement results, the data set contains a total of 150 groups of data, each class plants have 50 sets of data.)
- 2014-02-22 22:18:42下载
- 积分：1
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串口调试工具源码
【实例简介】
- 2021-05-20 14:39:31下载
- 积分：1
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Server dow
说明： emulator serv 752 wyd c++ code brazil, emulator serv 752 wyd c++ code brazil
- 2020-06-19 01:20:02下载
- 积分：1
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CPPtrining
华为C++中级培训教材,吐血奉献，挺好的资料。(huawei C++ trining)
- 2011-11-23 23:06:59下载
- 积分：1
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xy64
用BCB6.04编写的舍6入5看齐，奇进偶不进的数值修约法
根据GB8170—87《数值修约规则》［2］及GB3101—93附录B《数值修约规则》［3］，修约时不能简单地采用“4舍5入”的办法。应遵循的原则是：①拟舍弃的数字的最左一位数字等于、小于4，则舍去；大于、等于6，则进1。②拟舍弃数字的最左一位数字等于5，若其右边数字并非全部为“0”时，则进1；其右边数字皆为“0”时，所拟保留的末位数字若为奇数则进1，若为偶数或“0”则不进。(BCB6.04 prepared with care in line 6 to 5, Ki Jin Jin does not even repair some of the numerical method in accordance with GB8170-87 Numerical revision of the rules [2] and GB3101-93 Appendix B Numerical revision of the rules [3], when revision can not simply use 4 homes 5 in approach. Should follow the principle is: ① to give up most of the figures, a figure equivalent to the left, less than 4, then rounding greater than, equal to 6, then enter 1. ② figures to be the most left-up a digital equivalent to 5, if not all of the right figure for the 0 , then enter 1 its right figures are 0 when the bottom of the figures to be retained if it is an odd number into 1, if an even number or 0 does not enter.)
- 2008-04-25 11:58:05下载
- 积分：1
