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gkgosvj
蓝牙编解码代码,开源代码,资源非常不好找(Bluetooth codec code, open source code, resources are very difficult to find)
- 2019-01-01 00:03:49下载
- 积分：1
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kalmanfilter
说明： 基于嵌入式C语言，在ARM平台实现用于组合导航的卡尔曼滤波算法(include kalman_init();kalman();kalman_Q_R_H()....etc)
- 2021-03-31 19:19:08下载
- 积分：1
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HttpRequestDemo-master
说明： c# 实现 http请求，post，get，xml，json(C# implements HTTP requests)
- 2019-03-13 09:12:41下载
- 积分：1
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IEC104NASlave
说明： C++开发104协议，支持主从站。支持多客户端连接(C++ develops 104 protocol to support master and slave stations. Support multi-client connection)
- 2020-06-21 04:20:02下载
- 积分：1
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windows xp下的虚拟串口设备驱动
在windows xp操作系统下开发虚拟串口驱动(Developing virtual serial port driver under Windows XP operating system)
- 2020-08-28 11:28:13下载
- 积分：1
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HT16C22
段码屏驱动芯片ht16c22驱动程序，包含初始化及对ROM的读写操作。( U6BB5 u7C1 u5C4F u9A1 u2A1 u52AF u7Ac)
- 2020-10-02 23:17:40下载
- 积分：1
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ax.25-test
AX.25业余无线电数据通信协议通信的实现程序，包括打包和解包。(A program for packeting and unpacking AX.25 protocol.)
- 2021-03-19 10:49:19下载
- 积分：1
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cavity2d
palabos基本的经典方腔流动，2d模型，初学者必备(Palabos classical square cavity flow, 2d model.Essential for beginners)
- 2020-06-23 12:20:02下载
- 积分：1
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zoj1094
zoj094
Matrix multiplication problem is a typical example of dynamical programming.
Suppose you have to evaluate an expression like A*B*C*D*E where A,B,C,D and E are matrices. Since matrix multiplication is associative, the order in which multiplications are performed is arbitrary. However, the number of elementary multiplications needed strongly depends on the evaluation order you choose.
For example, let A be a 50*10 matrix, B a 10*20 matrix and C a 20*5 matrix.
There are two different strategies to compute A*B*C, namely (A*B)*C and A*(B*C).
The first one takes 15000 elementary multiplications, but the second one only 3500.
Your job is to write a program that determines the number of elementary multiplications needed for a given evaluation strategy.
(Matrix multiplication problem is a typical example of dynamical programming.
Suppose you have to evaluate an expression like A*B*C*D*E where A,B,C,D and E are matrices. Since matrix multiplication is associative, the order in which multiplications are performed is arbitrary. However, the number of elementary multiplications needed strongly depends on the evaluation order you choose.
For example, let A be a 50*10 matrix, B a 10*20 matrix and C a 20*5 matrix.
There are two different strategies to compute A*B*C, namely (A*B)*C and A*(B*C).
The first one takes 15000 elementary multiplications, but the second one only 3500.
Your job is to write a program that determines the number of elementary multiplications needed for a given evaluation strategy.
)
- 2012-06-10 10:38:53下载
- 积分：1
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模糊PID算法C语言程序-查表法
说明： 模糊控制pid查表法源码，有需要的可以下载看看，可以用于大家参考学习，一起进步(Fuzzy control pid source code, there is a need to download to see, can be used for everyone reference learning, progress together)
- 2020-04-08 11:24:56下载
- 积分：1
