登录
首页 » matlab » Simtoc

Simtoc

于 2012-07-22 发布 文件大小:216KB
0 184
下载积分: 1 下载次数: 3

代码说明:

  Translation validation: from Simulink to C

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • pso_2D
    matlab 的pso算法的程序 生成2D图像(The pso algorithm matlab program generates 2D images)
    2010-12-16 15:50:57下载
    积分:1
  • MATLABoder
    说明:  matlab的命令大全,希望对大家有帮助呵呵,主要是一些命令咯 (Matlab orders, hope to help you, is mainly some orders)
    2010-04-11 15:51:44下载
    积分:1
  • likelihood-DOA
    信号数目估计错误的最大似然波达方向估计的性能分析(The number of signal estimation error of maximum likelihood DOA estimation performance analysis)
    2013-12-26 12:59:21下载
    积分:1
  • RAYLEIGHFADINGMODELGENERATIONwithcodin
    RAYLEIGH FADING MODEL GENERATION
    2010-08-12 01:15:21下载
    积分:1
  • PID-MATLAB
    PID控制MATLAB仿真第二版,介绍关于PID的各种控制。(MATLAB simulation of the second version of PID control is introduced on a variety of PID control.)
    2010-11-02 19:21:33下载
    积分:1
  • STFT
    短时傅里叶变换MATLAB代码,主要是用于非线性信号分析(Short-time Fourier transform MATLAB code, mainly for nonlinear signal analysis)
    2016-04-11 19:49:12下载
    积分:1
  • 基于粒子群算法故障诊断
    说明:  基于matlab的例子群算法故障诊断实例(Example group algorithm fault diagnosis based on MATLAB)
    2020-10-30 21:09:57下载
    积分:1
  • QoS-multicast-Matlab
    关于QoS组播路由的Matlab源代码,有兴趣的网友可以参考一下。(QoS multicast routing on the Matlab source code, interested users can refer to.)
    2008-01-07 14:37:41下载
    积分:1
  • convolution
    convolution implemented in gui
    2010-06-18 03:47:52下载
    积分:1
  • YTY_GA_Final
    To find the largest fitness value and its location 寻找最大适应性及相应的位置! Population N=50;crossover bits=n/2 (half of bits of an individual) with random locations,mutation bits = 4 种群数 N=50,交换位数= n/2, 即个体位数的一半,且位置随机; 变异位数统一取为4; Nc=20,28,36,44,individuals for crossover(交换的个数)。 Nm=1,5,10,15, individuals for mutation(变异的个数)。 (To find the largest fitness value and its location to find the location of the maximum adaptability and the corresponding! Population N = 50 crossover bits = n/2 (half of bits of an individual) with random locations, mutation bits = 4 population size N = 50, exchange digits = n/2, ie half of the median individual, and random position variation is taken as unity median 4 Nc = 20,28,36,44, individuals for crossover (exchange number). Nm = 1,5,10,15, individuals for mutation (the number of variations.))
    2010-12-27 21:23:27下载
    积分:1
  • 696516资源总数
  • 106562会员总数
  • 4今日下载