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lyapunov
lyapunov 指数计算方法 MATLAB程序代码(lyapunov matlab code)
- 2014-11-30 21:07:28下载
- 积分：1
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BLFilter
我用C#实现的一个双边滤波器，使用unsafe代码，用指针获取像素。(I use C# to achieve a bilateral filter, use unsafe code to get pixel pointer.)
- 2012-09-18 09:44:15下载
- 积分：1
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inv
求素数域GF(p)中元素的逆元（可用于LTE中频域时域ZC序列的转换)
注：Matlab自带的函数gf只支持gf(2^m)，本程序p可以支持任意素数。(obtain inverse of the element of prime field GF(p))
- 2012-07-07 15:24:44下载
- 积分：1
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yichuansuanfa
该代码为遗传算法matlab代码，其中代码都附有详细说明(The code for the genetic algorithm matlab code, which is accompanied by a detailed description of the code)
- 2014-02-05 15:06:31下载
- 积分：1
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Digitalfilersourcecode
这是用MATLAB来实现的数字滤波器,对于做光学三维测量和数字通信方面都很有帮助(This is achieved using MATLAB digital filter, for to do three-dimensional optical measurement and digital communications are helpful)
- 2009-03-11 20:48:20下载
- 积分：1
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wavelet
说明： 以Morlet小波作为网络隐含层的变换基函数小波神经网络MATLAB源程序(As a Morlet wavelet transform of the network hidden layer wavelet neural network basis function MATLAB source code)
- 2009-08-23 09:13:15下载
- 积分：1
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Antenna2008
Optic communication antenna angle
- 2006-12-18 19:55:53下载
- 积分：1
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MATLABfortheLDAalgorithandresults
MATLAB实现的LDA算法以及运行结果截图,(MATLAB implementation of the results of LDA algorithm and run shots,)
- 2010-10-25 19:19:28下载
- 积分：1
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MATLAB
对噪声信号中的正弦信号，通过Pisarenko谐波分解方法、Music算法和Esprit算法进行频率估计，信号源是： 其中， ， ， ； 是高斯白噪声，方差为 。使用128个数据样本进行估计。 1、用三种算法进行频率估计，独立运行20次，记录各个方法的估计值，计算均值和方差； 2、增加噪声功率，观察和分析各种方法的性能。(Sinusoidal signal in the noise signal through the Pisarenko harmonic decomposition method, Music algorithms and Esprit frequency estimation algorithm, the signal source is: where,,, a Gaussian white noise, variance. 128 data samples used to estimate. 1, with three kinds of frequency estimation algorithm, run independently 20 times, record the estimated value of each method to calculate the mean and variance 2, the increase in noise power, observation and analysis of the performance of various methods.)
- 2021-03-24 14:49:14下载
- 积分：1
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pingfenchengxu
设计一个可以输入若干评委分数的表单，可以通过两个for循环分别找出分数的最大值和最小值，存入到两个变量，把评委的分数存入到一个数组中，计算时去掉找出的最大值和最小值即可得出最后得分。
(You can enter a number of judges to design a fractional form, you can find the maximum and minimum scores for each through two loops, credited to two variables, the judges scores deposited into an array, remove the calculation to find out the maximum and minimum values to arrive at a final score.)
- 2013-12-23 21:50:31下载
- 积分：1
