登录
首页 » matlab » Exploring-Mathematics-with-MuPAD_MTManual10

Exploring-Mathematics-with-MuPAD_MTManual10

于 2013-08-17 发布 文件大小:199KB
0 201
下载积分: 1 下载次数: 2

代码说明:

  Using to call in matlab

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • chap1_27
    该程序利用matlab语言编写的,实现的是部分微分PID算法及仿真功能(The program using matlab languages, achieved a partial differential PID algorithm and simulation)
    2007-11-29 12:21:55下载
    积分:1
  • matlab
    书名:数字通信原理_基于matlab仿真计算 书中很多 matlab 源码,适合在校学生熟悉了解matlab在数字通信中的应用(Title: Principles of digital communication matlab simulation based on _ a lot of matlab source book for students to become familiar with matlab in the digital communication)
    2007-12-12 10:44:13下载
    积分:1
  • calculation-of-PBG-by-TMM
    利用传输矩阵法计算一维光子晶体能带结构的matlab程序,包含m文件以及计算案例的word文档。(Using the transfer matrix method to calculate one-dimensional photonic crystal band structure of the matlab program, including the case of m-file and to calculate the word document.)
    2011-11-28 21:18:51下载
    积分:1
  • dvhop
    wireless sensor network localization estimation using distance vector one hop
    2015-02-24 17:09:13下载
    积分:1
  • THE-Calender
    一个简单的matlabGUI界面,设计的一个日历,有时间和星期的简单源码(The a simple matlabGUI interface, design a calendar, a simple source of the time and day of the week)
    2012-12-04 17:33:23下载
    积分:1
  • backpropagation_class
    A MLP code with backpropagation training algorithm designed for classification problems.
    2010-11-17 06:08:55下载
    积分:1
  • 2
    说明:  案例为运用最有控制原理,实现对火星探测器小推力变轨的控制实现。应用matlab仿真实现(Case for the use of the most control theory, to achieve the low-thrust orbit Mars probe control implementation. Application of matlab simulation)
    2013-09-29 17:11:11下载
    积分:1
  • matlab
    OMP算法的一维信号实现matlab 源码 基于压缩感知的(OMP algorithmn )
    2011-11-17 15:11:16下载
    积分:1
  • mimo2
    mimo capacity plot for different nt*nr
    2010-08-24 19:19:02下载
    积分:1
  • LTE_System_Level_1.4_r570
    To solve this instance of the decision problem we must determine whether there is a truth value (TRUE or FALSE) we can assign to each of the variables (x1 through x4) such that the entire expression is TRUE. In this instance, there is such an assignment (x1 = TRUE,x2 = TRUE, x3=TRUE, x4=TRUE), so the answer to this instance is YES. This is one of many possible assignments, with for instance, any set of assignments including x1 = TRUE being sufficient. If there were no such assignment(s), the answer would be NO.
    2012-04-23 22:00:12下载
    积分:1
  • 696518资源总数
  • 106155会员总数
  • 8今日下载