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simulink_123
simulink仿真教程,蹦极模型建模和仿真,传递函数,状态模型(simulink simulation tutorial, bungee modeling and simulation, transfer function, state model)
- 2014-09-28 18:49:09下载
- 积分:1
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涡旋电磁波相位图
说明: 不同模态OAM的相位图,电场场强图,及用箭头表示相位变化。(Phase diagram, electric field strength diagram of OAM with different modes and phase change indicated by arrows.)
- 2020-04-03 20:24:33下载
- 积分:1
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fft
fft的应用,包正旋信号,脉冲信号等通
过fft变换所产生的变化(fft applications, including the sine signal, pulse signals generated by changes in fft transform)
- 2011-05-09 10:25:37下载
- 积分:1
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wave1
自定义信号,用于梯形边界奇异点检测matlab代码, 和三个小波去噪分解的代码(Custom signal singularity detection for trapezoidal matlab code boundary, and three wavelet denoising decomposition code)
- 2011-05-09 14:37:44下载
- 积分:1
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image-quyu
matlab 实现图像的区域分块处理 区域函数。。(image processing)
- 2012-04-28 18:40:51下载
- 积分:1
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matlab-Tutorial-ebook
这是一本关于MATLAB的电子书,格式是PDF,里面介绍很详细,是新手学习的好帮手。(This is a book about MATLAB format is PDF, which introduced a very detailed novice learning a good helper.)
- 2012-10-17 16:36:13下载
- 积分:1
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CHAP10_1
确定性单臂机械手的PD+前馈控制 matlab仿真
(uncertainty arm manipulator PD feedforward control Matlab simulation)
- 2006-11-22 16:59:46下载
- 积分:1
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Ant-colony-algorithm
蚁群算法连续函数优化问题matlab程序(Ant colony algorithm for continuous function optimization problems in MATLAB programming)
- 2015-03-20 17:32:38下载
- 积分:1
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YTY_GA_Final
To find the largest fitness value and its location
寻找最大适应性及相应的位置!Population N=50;crossover bits=n/2 (half of bits of an individual) with random locations,mutation bits = 4 种群数 N=50,交换位数= n/2, 即个体位数的一半,且位置随机;
变异位数统一取为4;
Nc=20,28,36,44,individuals for crossover(交换的个数)。Nm=1,5,10,15, individuals for mutation(变异的个数)。(To find the largest fitness value and its location to find the location of the maximum adaptability and the corresponding! Population N = 50 crossover bits = n/2 (half of bits of an individual) with random locations, mutation bits = 4 population size N = 50, exchange digits = n/2, ie half of the median individual, and random position variation is taken as unity median 4 Nc = 20,28,36,44, individuals for crossover (exchange number). Nm = 1,5,10,15, individuals for mutation (the number of variations.))
- 2010-12-27 21:23:27下载
- 积分:1
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shujuyuchuli
用于随机数据的数据预处理,没有解压密码,直接使用(random data for the data preprocessing, not extracting passwords used directly)
- 2006-06-22 09:58:44下载
- 积分:1