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block_mp
压缩感知里面的稀疏重建问题,在原来MP的算法的基础上,提出了分块的思想,即将原子库分块后,测试算法的性能。(Compressive sensing is refered as the block sparse algorithm is described,that is based on the original MP algorithm,and the atom libruary is divided into blocks ,and the performance is testified.)
- 2010-10-27 19:10:08下载
- 积分:1
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yuce
建立ARMA模型,进行数据的预测,效果很好,这里是其中的代码(the code of the ARMA)
- 2011-08-21 15:18:55下载
- 积分:1
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BookmarkWidgetService
Bookmark Widget Service Source Code for Andriod.
- 2013-11-14 23:58:26下载
- 积分:1
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MDwnn
多输入多输出的小波网络模型,需安装matlab神经网络工具箱用的是青岛海洋大学学报上那篇论文的模型,嵌入了开发的初始化算法,程序里有较为详细的说明,很好用(Multiple-input multiple-output wavelet network model, the need to install matlab neural network toolbox is used Qingdao Ocean University Journal article thesis model, embedded in the development of the initialization algorithm, the procedure has a more detailed explanation, very good use)
- 2008-01-03 21:27:06下载
- 积分:1
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LMS_filter
simple Least Mean Square(LMS) filter
- 2010-05-27 14:55:55下载
- 积分:1
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my_NLMS_good
自己编写的基于nlms的回波消除算法,直接能运行(I have written based nlms echo cancellation algorithm can be run directly)
- 2013-12-04 16:08:55下载
- 积分:1
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daolibai
本程序可以实现利用神经网络算法对倒立摆的稳定控制(Stability control procedures can be achieved using neural network algorithm for inverted pendulum)
- 2015-02-01 14:45:03下载
- 积分:1
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ga
说明: 该程序用BASE-10遗传算法模拟简单函数的优化。首先,我们概述了遗传算法的一些背景信息,并定义了一些术语。接下来,我们将解释如何将该程序用于您自己的目的,并作为一个示例演示如何解决优化问题。(This program simulates the optimzation of a simple function with
a base-10 genetic algorithm. First, we outline some background
information on GAs and define some terminology. Following this,
we explain how to use the program for your own purposes and as an
example we show how to solve an optimization problem.)
- 2019-06-03 09:38:40下载
- 积分:1
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imacolorthreshold
this matlab code to help you finding the Color Image Threshold
- 2010-09-29 14:41:17下载
- 积分:1
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advancenewton
说明:
改进的牛顿法求解:
方程的构造方法:给出[0,1]区间上的随机数(服从均匀分布)作为方程的根p*.
设你的班级数为a3,学号的后两位数分别为a2与a1,从而得到你的三次方程
例如:你的31班的12号,则你的方程是21x3+60x2+2x+a0=0的形式.
方程中的系数a0由你得到的根p*来确定.
(improve Newton's method : Construction of the equation : given interval [0,1] on the random number (subject to uniform distribution) as the root equation p*. set up your classes at a3, after learning of the double-digit for a1 and a2, so you get the three equations for example : Your 31 classes on the 12th, then your equation is 21x3 60x2 2x a0 = 0 forms. the equation coefficients a0 you get from the root of p* to determine.)
- 2005-12-03 18:16:08下载
- 积分:1