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motionComp
this is used to find motion compensation. this is matlab code
- 2009-05-05 17:09:37下载
- 积分：1
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matlab-Kmeans
利用matlab实现kmeans聚类算法的简单实现代码(matlab kmens algrithom )
- 2012-03-26 08:59:53下载
- 积分：1
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ExtendedKalmanFilter
Extended Kalman Filter Tracking Object in 3-D(Assume that we want to track an object moving in 3-D space with constant velocity. Our instruments observe bearing, range and high(cylindrical coordinates). However, of an interest are rectangular coordinates. Since transformation is non-linear this requires use of extended Kalman filter.
Because transformation is non-linear between X,Y and Range,Bearing and linear between Z and high(Z is height), this problems serves as a good comparason of how well extended Kalman filter can perform. By comparing its linear estimation error in Z to non-linear estimations in X and Y, we can judge how non-familiarities effect estimation. )
- 2012-05-14 22:14:04下载
- 积分：1
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rls-algorithm
RLS波束形成代码，供大家参考学习，关于阵列信号处理的内容。(RLS beamforming code, for your reference learning, about the content of the array signal processing.)
- 2014-11-13 20:38:10下载
- 积分：1
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MATHMODL
matlab算法工具箱，本工具箱主要包含三部分内容
(支持平台MATLAB5.3或5.2,Symbolic math,optim,spline,stats)
1. MATLAB常用数学建模工具的中文帮助
2. 贡献MATLAB数学建模工具(打*号)
3. 中国大学生数学建模竞赛历年试题MATLAB程序(Almost algorithm matlab toolbox)
- 2013-10-23 16:03:07下载
- 积分：1
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pdcch
pdcch信道的仿真程序，对于做这方面研究的是很好的借鉴程序(a simulation for pdcch channel which is a good example for students)
- 2013-05-08 16:22:38下载
- 积分：1
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SC_sunny_RI
本模型可用于计算晴天下北半球任意地区任意角度下集热器太阳日辐射强度(Any angle collector solar radiation calculation model)
- 2012-04-07 01:46:33下载
- 积分：1
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RCB
说明： 鲁棒Capon算法的程序实例仿真，便于初学者学习，内附有论文，可参考对照(Program example simulation of robust Capon algorithm)
- 2020-12-09 22:47:26下载
- 积分：1
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jiaozhengbijiao
传统频谱校正方法和全相位频谱校正法比较，可以看出全相位频谱校正的优势很明显(Traditional correction method and full-spectrum phase spectrum correction method of comparison, we can see the advantages of all phase spectrum correction obviously)
- 2009-12-07 10:16:53下载
- 积分：1
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fahanshu
利用罚函数法求解下列问题：求f=x1^2+4*x2^2的最小值，其中要满足：x1-x2-1≤0
-x1-x2+1≤0
x2-1≤0
(Using penalty function method to solve the following questions: o f = x1 ^ 2+ 4* x2 ^ 2 minimum value, which will meet: x1 x2-1-0 or
-x1 x2+ 1 or 0-
X2-1 or 0
)
- 2011-12-19 15:35:50下载
- 积分：1
