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ch01
ANSYS教程,《ANSYS有限元分析实用教程》源代码("ANSYS finite element analysis of practical course," the source code)
- 2010-05-25 14:26:26下载
- 积分:1
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Euler_2D
二维Euler方程的Jameson求解方法(Jameson solution of two-dimensional Euler equations)
- 2020-09-09 21:18:03下载
- 积分:1
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final_robotSearch-1.0_2learn-it
new robot search algorithms
- 2011-05-03 22:48:14下载
- 积分:1
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PM
说明: 彭曼公式主要是计算蒸散发量,在水文和气象中有广泛的应用(Penman formula to calculate evapotranspiration primarily, widely used in hydrology and meteorology)
- 2014-10-27 17:38:05下载
- 积分:1
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nodefstrainstressfiberla002
说明: 复合材料损伤,复合材料层间分层,损伤,刚度退化、衰减(Composite damage, delamination of composite layers, damage, stiffness degradation, attenuation)
- 2019-04-08 11:14:11下载
- 积分:1
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Sola
Fortran编写的VOF经典算法,SOLA-VOF(VOF classical algorithms written in Fortran, SOLA-VOF)
- 2021-01-17 23:38:48下载
- 积分:1
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waveFieldSimulationProgramOfILayer
Ⅰ层模型声波波场数值模拟源程序,对各向异性介质中的地震波进行研究,无论是进行野外施工技术研究,还是进
行岩层岩性参数与波动方程之间的关系的研究,或者是进行各向异性介质中地震波
场处理与分析的研究,都离不开各向异性的地震波场数值模拟。(Ⅰ layer model numerical simulation of acoustic wave source for seismic waves in anisotropic media research, whether in carrying out field work research, or to rock lithology parameters and the wave equation of the relationship between research, or to the anisotropy of seismic wave fields in media processing and analysis of the study, are inseparable from anisotropy of seismic wave field numerical simulation.)
- 2009-11-06 15:38:51下载
- 积分:1
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Matlab
RD成像算法,快速傅里叶变换函数,适合学习(RD imaging algorithm, fast Fourier transform function, suitable for learning)
- 2020-08-13 18:58:29下载
- 积分:1
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11087 统计逆序对
说明: Description
设a[0…n-1]是一个包含n个数的数组,若在ia[j],则称(i, j)为a数组的一个逆序对(inversion)。
比如 有5个逆序对。请采用类似“合并排序算法”的分治思路以O(nlogn)的效率来实现逆序对的统计。
一个n个元素序列的逆序对个数由三部分构成:
(1)它的左半部分逆序对的个数,(2)加上右半部分逆序对的个数,(3)再加上左半部分元素大于右半部分元素的数量。
其中前两部分(1)和(2)由递归来实现。要保证算法最后效率O(nlogn),第三部分(3)应该如何实现?
此题请勿采用O(n^2)的简单枚举算法来实现。
并思考如下问题:
(1)怎样的数组含有最多的逆序对?最多的又是多少个呢?
(2)插入排序的运行时间和数组中逆序对的个数有关系吗?什么关系?
输入格式
第一行:n,表示接下来要输入n个元素,n不超过10000。
第二行:n个元素序列。
输出格式
逆序对的个数。
输入样例
5
2 3 8 6 1
输出样例
5(Set a[0... N-1] is a n array containing n numbers. If there is a [i] > a [j] i n the case of I < j, then (i, j) is a n inversion pair of a array.
For example, has five reverse pairs. Please use the idea of "merge sorting algorithm" to achieve the statistics of inverse pairs with O (nlogn) efficiency.
The number of inverse pairs of a sequence of n elements consists of three parts:
(1) The number of reverse pairs in the left half, (2) the number of reverse pairs in the right half, (3) the number of elements in the left half is greater than that in the right half.
The first two parts (1) and (2) are implemented by recursion. To ensure the final efficiency of the algorithm O (nlogn), how should the third part (3) be implemented?
Do not use O (n ^ 2) simple enumeration algorithm to solve this problem.)
- 2019-01-07 23:52:06下载
- 积分:1
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sca_pec_cyl_efie_mm
矩量法的fortran程序,利用矩量法求解球散射的程序,希望大家好好学习(mom fortran program)
- 2021-02-21 12:59:42下载
- 积分:1