-
Wind_Turbine_Model
windmill turbine models
- 2011-09-22 13:56:44下载
- 积分:1
-
GMM_Examples_v2014_08_04
GMM PARAMETERS AN BE EASILY IMPLIMENTEED USING EM TECHNIQUE.EVENTHOUGH THIS MODEL IS COMPLEX ,E XPECTATION MAXIMAISATION FINDS AN EASYWAY TO CALCULATE THE PARAMETERS IN AN EFFICIENT WAY.
- 2015-04-17 09:56:42下载
- 积分:1
-
culture
文化算法源代码,基于matlab编写的文化算法源代码。(Cultural algorithm source code, written culture based on matlab algorithm source code.)
- 2012-05-27 15:11:32下载
- 积分:1
-
keshe1
通信系统的设计,课程实际做的,有编码、调制解调等等部分构成,简单,但一定出结果(the design of communication system)
- 2015-04-06 14:46:51下载
- 积分:1
-
ecu
Ecuacion necesaria para metodo de multiplicacion
- 2009-10-26 18:13:07下载
- 积分:1
-
GA-in-Matlab
用MATLAB实现遗传算法,介绍怎么实现(To achieve genetic algorithms using MATLAB)
- 2013-02-12 04:36:56下载
- 积分:1
-
ODE4
Matlab中的四阶龙格库塔法m文件。 (Matlab in the fourth-order Runge-Kutta method m file.)
- 2007-11-25 13:45:45下载
- 积分:1
-
DSPusingmatlab
这是数字信号处理的几个典型例程,都是有关于最基本概念方面的,对初学者有帮助(Digital Signal Processing This is a typical course of a few are on the most basic concepts, and helpful for beginners)
- 2009-07-11 13:22:38下载
- 积分:1
-
we
说明: 七单元天线阵DOA估计
clear clc
d=1 天线阵元的间距
lma=2 信号中心波长
q1=1*pi/4 q2=1*pi/3 q3=1*pi/6 q4=3*pi/4 四输入信号的方向
A1=[exp(-2*pi*j*d*[0:6]*cos(q1)/lma)] 求阵因子
A2=[exp(-2*pi*j*d*[0:6]*cos(q2)/lma)]
A3=[exp(-2*pi*j*d*[0:6]*cos(q3)/lma)]
A4=[exp(-2*pi*j*d*[0:6]*cos(q4)/lma)]
A=[A1,A2,A3,A4] 得出A矩阵
n=1:1900
v1=.015 四信号的频率
v2=.05
v3=.02
v4=.035
d=[1.3*cos(v1*n) 1*sin(v2(we)
- 2010-05-06 15:26:50下载
- 积分:1
-
rvctools9.8
MATLAB中用于工业机器人开发,包括基本函数机器人使用函数工具箱(robot toolbox 9.8)
- 2014-09-26 20:06:24下载
- 积分:1