网站首页

CS-Channel-Estimation

于 2013-10-25 发布文件大小:11KB

 0  170

下载积分: 1 下载次数: 80

我要下载

代码说明：

信道估计程序，ieee发表的文章对应的原码，本人已经验证，可以使用。(Channel estimation procedures, ieee post corresponding to the original code, I have verified that you can use.)

文件列表：

CS-Channel Estimation
.....................\channel.m,634,2012-02-06
.....................\LS_MSE_calc.m,424,2011-05-03
.....................\MMSE_MSE_calc.m,514,2011-05-04
.....................\MSE_com.m,2963,2011-05-04
.....................\omp.m,941,2011-04-13
.....................\seqnum_compare.fig,93184,2011-07-30
.....................\seqnum_compare.m,1438,2011-05-04

下载说明：请别用迅雷下载，失败请重下，重下不扣分！

发表评论

0 个回复

3D
说明：自动生成三维的多孔介质，对多孔介质研究的学者有用(Automatic generation of three-dimensional porous media, porous media studies scholars Useful)

2015-10-01 13:54:48下载

积分：1
Recursive_integer_division
递归法求解整数划分。整数划分，是指把一个正整数n写成如下形式： n=m1+m2+…+mi （其中mi为正整数，并且1 <= mi <= n），则{m1,m2,...,mi}为n的一个划分。如果{m1,m2,...,mi}中的最大值不超过m，即max(m1,m2,...,mi)<=m，则称它属于n的一个m划分。这里我们记n的m划分的个数为f(n,m) (Recursive method integer division. Integer division, refers to a positive integer n written as follows: n = m1+m2+ ...+mi (where mi is a positive integer, and 1 < = mi < = n), then {m1, m2, ..., mi} is a division of n. If {m1, m2, ..., mi} does not exceed the maximum value of m, i.e., max (m1, m2, ..., mi) < = m, m n is said that it belongs to a division. Where m is the number of division n our mind is f (n, m) )

2014-02-06 14:21:38下载

积分：1
xu(1)
饱和时滞系统matlab相图,给出输入变量的上下界(The matlab phase diagram of the saturated time-delay system is given, and the upper and lower bounds of the input variables are given)

2016-09-30 08:04:40下载

积分：1
NEW-LEACH-matlab.txt
对经典协议LEACH的改进版本，可以出图3个，对初学很有帮助，大家有兴趣的可以看看。(LEACH agreement on an improved version of the classic, you can plot three, very helpful for beginners, we are interested can look at.)

2014-01-20 17:22:06下载

积分：1
CA0LUR83
自己写的matlab小程序，用于解方程组。可以参考下(Their own small programs written in matlab for solving equations. Can refer to)

2011-09-27 10:15:02下载

积分：1
A
Execution cmd.rarExecution cmd.rarExecution cmd.rarExecution cmd.rarExecution cmd.rarExecution cmd.rar

2013-12-12 22:11:11下载

积分：1
Vis
Supermarket cashier system .doc(Supermarket cashier system )

2014-01-08 22:59:33下载

积分：1
pb
phone book for add or remove telephone numbers in text file

2014-01-12 19:01:34下载

积分：1
POS-code
粒子群算法的具体代码，简单易行非常好用，放在word中，复制出来可直接使用(PSO algorithm specific code is very simple to use, on the word, copy it can be used directly)

2015-04-09 17:43:58下载

积分：1
vector_4
with study image process sample program

2015-02-21 15:33:29下载

积分：1

696516资源总数
106409会员总数
8今日下载

CS-Channel-Estimation

0 个回复

热门标签

热门下载