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Joseph
说明： 约瑟夫问题，四种解法，分别是静态链表，顺序表两种和循环链表(Joseph problems, the four solution, namely a static list, order form and the cycle of two lists)
- 2010-04-23 08:20:53下载
- 积分：1
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00
说明： 还是通讯录系统 增删改查 课程设计 本科学校要求的数据结构课程设计(Or address book CRUD the data structures required by the curriculum design undergraduate schools curriculum design)
- 2012-06-17 21:36:24下载
- 积分：1
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SplitADT
链表L，创建公有成员函数Split（A,B ），创建2个新表A,B，使的A 中含有L中奇数位置元数，B中含L偶数位置元数
(Chain L, create public member function Split (A, B), to create two new tables A, B, A so containing L odd position of a few yuan, B-L even a few locations yuan)
- 2007-03-30 20:48:18下载
- 积分：1
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Haffman
将一组数组转换为哈夫曼编码，使用数据结构中的二叉树功能实现(Convert an array to Haffman code)
- 2016-01-30 14:56:20下载
- 积分：1
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Figure-topological-sort
说明： 拓扑排序
对一个 有向无环图 G进行拓扑排序，是将G中所有顶点排成一个线性序列，使得图中任
意一对顶点u和v，若u，v ∈E，则u在线性序列中出现在v之前。
通常，这样的线性序列称为满足拓扑次序的序列，简称 拓扑序列 。
注意：
①若将图中顶点按拓扑次序排成一行，则图中所有的有向边均是从左指向右的。
②若图中存在有向环，则不可能使顶点满足拓扑次序。
③一个DAG的拓扑序列通常表示某种方案切实可行。 (Topological sort
In a directed acyclic graph G topological sort, is all vertices will G formed a linear sequence, make diagram post
Meaning a pair of vertex u and v, if u, v ∈ E, then u in linear sequence in which they appear in v before.
Usually, such linear sequence sequence of topological order called meet, abbreviation topology sequence.
Note:
(1) if the diagram according to the topology order line vertices, then figure all from left to right edge are pointing.
(2) if the figure to exist in the ring, is impossible to have the vertex meet topological sequence.
(3) a DAG topological sequence usually expressed some scheme is feasible.
)
- 2011-03-22 17:19:14下载
- 积分：1
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bag1
使用不同的方法解决背包问题：本算法采用的是动态规划方法，比较好的解决背包问题。(Use different methods to solve knapsack problem: The algorithm is a dynamic programming approach, a better solution to knapsack problem.)
- 2011-07-16 18:40:31下载
- 积分：1
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hannuota
分析汉诺塔，选择合适方法编程实现汉诺塔问题的解答。(Analysis of the Tower of Hanoi, select the appropriate method of programming the answers of the Tower of Hanoi problem.)
- 2012-05-22 18:48:33下载
- 积分：1
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arc
运用二叉树求代数表达式的值，将代数表达式的每个符号用二叉树结点表示，遍历图的每一结点，按结点值得不同采用不同运算方式(Solving algebraic expressions binary tree)
- 2012-06-23 19:52:38下载
- 积分：1
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migong
简单的迷宫问题，有点土，还望大家多指点指点，在此感激不尽。(????? mad spasm, ? Tang Gao, ? oligonucleotide ??? Ning Ning ? ?, Hitomi ?????.)
- 2008-07-05 00:11:37下载
- 积分：1
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DP
说明： 动态规划是用空间换时间的一种方法的抽象。(Dynamic programming is to use space in time a method of abstract.)
- 2012-11-12 08:52:31下载
- 积分：1
