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onduleurMLI
Simulink of onduleur MLI
- 2013-04-15 00:04:24下载
- 积分：1
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xuanbiliang
采用模态叠加法和Newmark方法求解悬臂梁的响应，可以直接运行，经验证程序正确(Modal superposition method and Newmark method for solving cantilever response, and can directly run the program properly validated)
- 2020-12-21 15:59:09下载
- 积分：1
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abc
全书包含 390多个计算范例。所有算例的程序是可靠、完整的。读者可以在自己的 MATLAB环境中
完全准确地重现本书所提供的算例结果。算例的举一反三，将使读者很快掌握要领，从模仿走向灵活应用(The book contains over 390 examples of the calculation. All examples of the program is reliable and complete. Readers in their own MATLAB environment, completely and accurately reproduce the book provided by the numerical results. Example of the lesson should be learned, will enable readers to quickly grasp the essentials, from imitation toward flexible application of)
- 2009-09-29 22:00:33下载
- 积分：1
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chap5
在matlab中计算图像中的欧拉数，这是一个很有创新的例子(In matlab to calculate the Euler number of images, this is a great example of innovation)
- 2008-05-21 22:32:16下载
- 积分：1
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KPCA_vs_PCA
原创的基于Matlab 的kpca 源程序，大家一起学习一下(Matlab-based kpca original source, everyone works together to learn about)
- 2010-03-06 00:23:22下载
- 积分：1
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pca(matlab)
一个PCA用于人脸识别的程序，不知道有没有，先传了供大家参考下。 (a PCA for face recognition procedures, I do not know any first-of reference for everyone under.)
- 2006-07-16 12:35:50下载
- 积分：1
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verify
计算交叉耦合的耦合矩阵矩阵 (coupling chebyshev)
- 2011-06-24 15:22:00下载
- 积分：1
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imaging-processing
Imaging processing segmentacja
- 2011-10-04 16:41:47下载
- 积分：1
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particle-design
最经典的matlab介绍微粒群算法的书，不好买的。(The most classic PSO algorithm matlab introduction of the book, not bought.)
- 2013-09-29 16:02:23下载
- 积分：1
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equal-area-critirea
E=input( enter the generator voltage: )
V=input( enter the infinite bus voltage: )
Gx=input( enter the reactance of generator: )
L1x=input( enter the line reactance: )
L2x=input( enter the line reactance: )
L3x=input( enter the line reactance: )
L4x=input( enter the line reactance: )
Pi=input( enter the input power: )
X1=Gx+L1x+((L2x*L3x)/(L2x+L3x))+L4x
Pm1=E*V/X1
DO=asin(Pi/Pm1)
A=((L2x*L3x)/(2*(L2x+L3x)))
C=A
B=((L3x/2)^2)/(L2x+L3x)
X2=(Gx+L1x+A)+(L4x+A)+(Gx+L1x+A)*(A+L4x)/B
Pm2=(E*V)/X2
X3=Gx+L1x+L2x+L4x
Pm3=(E*V)/X3
DC=input( enter the fault clearing angle: )
Dm=(3.14-asin(Pi/Pm3))
a1=quad( sin ,DO,DC)
A1=(Pi*(DC-DO)-Pm2*a1)
a2=quad( sin ,DC,Dm)
A2=Pm3*a2-Pi*(Dm-DC)
if(A2>=A1)
disp( the system is stable )
else
disp( the system is unstable )
end
Dcc=acos((Pi*(Dm-DO)-Pm2*(cos(DO))+Pm3*(cos(Dm)))/(Pm3-Pm2))
disp( critical clearing angle: )
Dcc
- 2012-09-11 22:46:05下载
- 积分：1
