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TowersOfHanoi
matlab source code
tower of hanoi!!
good luck!
- 2013-12-08 16:51:31下载
- 积分：1
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linepro2
对偶单纯形法求解线性规划问题，得到问题的最优解(Dual simplex method for solving linear programming problems, to obtain the optimal solution )
- 2011-04-28 13:56:48下载
- 积分：1
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25222-560
TD-SCDMA的物理层规范，具体介绍了信道复用和信道编码，对信道编码流程描述很清楚(TD-SCDMA standard in the physical layer, the specific details of the channel multiplexing and channel coding. right channel coding process description is very clear)
- 2006-12-05 12:04:02下载
- 积分：1
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SPRING-MASS-SYSTEM
关于弹簧质量块的一个误差空间控制Matlab仿真程序( SPRING MASS SYSTEM SIMULATION FOR ERROR SPACE CONTROL )
- 2012-05-14 11:38:26下载
- 积分：1
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ALGraph
This is a ALGraph program, helpful for software developers. It can be related to the data structure study of good.
- 2015-02-17 13:26:17下载
- 积分：1
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SF_Spline
基于matlab的三次样条插值算法程序(Matlab based on the cubic spline interpolation algorithm procedure)
- 2007-12-05 18:21:48下载
- 积分：1
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gray-system
灰色系统知道系统的一些简单信息，但是并没有完全了解该系统，只能根据统计推断或某种逻辑思维来研究该系统。(The gray system know some simple information system, but did not fully understand the system, to study the system can only be based on statistical inference, or some kind of logical thinking.)
- 2013-03-23 11:12:52下载
- 积分：1
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fftlms
天线的频域内LMs算法MATLAB仿真，天线阵列类型为圆阵。(The antenna frequency domain LMs algorithm MATLAB simulation, the type of circular array antenna array.)
- 2009-12-09 12:48:27下载
- 积分：1
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GA_TSP
这是基于遗传算法的matlab编写的TSP问题程序，希望有所帮助。(This is based on genetic algorithm matlab program written TSP problem, hope help.)
- 2011-07-20 16:51:08下载
- 积分：1
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YTY_GA_Final
To find the largest fitness value and its location
寻找最大适应性及相应的位置！ Population N=50；crossover bits=n/2 (half of bits of an individual) with random locations，mutation bits = 4 种群数 N=50，交换位数= n/2, 即个体位数的一半，且位置随机；
变异位数统一取为4；
Nc=20，28，36，44，individuals for crossover(交换的个数)。 Nm=1，5，10，15， individuals for mutation(变异的个数)。 (To find the largest fitness value and its location to find the location of the maximum adaptability and the corresponding! Population N = 50 crossover bits = n/2 (half of bits of an individual) with random locations, mutation bits = 4 population size N = 50, exchange digits = n/2, ie half of the median individual, and random position variation is taken as unity median 4 Nc = 20,28,36,44, individuals for crossover (exchange number). Nm = 1,5,10,15, individuals for mutation (the number of variations.))
- 2010-12-27 21:23:27下载
- 积分：1
