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Fingerprint
这是基于matlab编写的一套用于指纹识别的源码，可以即得即用，很是详细。(This is based on the preparation of a set of matlab source code for fingerprint recognition, which you can get that is used, it is detailed.)
- 2009-09-13 11:08:29下载
- 积分：1
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Bernoulli
This Simulink model simulates as an example the transmission and reception of random digital data modulated with GMSK. The purpose of this model is to illustrate how part of the GSM transmission and reception works. It also measures the BER, affected by an AWGN channel.
- 2009-05-04 01:18:27下载
- 积分：1
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21
说明： 阵列信号处理一个实例，适合初学者。能够深刻doa的具体思想,是CAPON和MUSIC方法的对比(An instance array signal processing, suitable for beginners. The specific ideological profound doa is of CAPON and the MUSIC method comparison)
- 2012-10-18 10:09:33下载
- 积分：1
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19854782sensor
lleach code under mathab for the simulation
- 2010-06-26 19:01:28下载
- 积分：1
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A-Web-Shareable-Real-World-Imaging-Problem-for
A Web-Shareable Real-World Imaging Problem for
- 2012-05-16 19:24:04下载
- 积分：1
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mskcode
matlab MSK调制解调代码。用一比特差分解调，带误码率图形。(MSK modulation and demodulation)
- 2020-12-31 10:39:04下载
- 积分：1
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LMS_RLS
自适应波速形成，RLS、LMS噪声对消器，，以及性能比较(Adaptive beamforming, RLS, LMS noise, as well as performance comparison canceller)
- 2013-12-15 12:53:04下载
- 积分：1
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we
说明： 七单元天线阵DOA估计
clear clc
d=1 天线阵元的间距
lma=2 信号中心波长
q1=1*pi/4 q2=1*pi/3 q3=1*pi/6 q4=3*pi/4 四输入信号的方向
A1=[exp(-2*pi*j*d*[0:6]*cos(q1)/lma)] 求阵因子
A2=[exp(-2*pi*j*d*[0:6]*cos(q2)/lma)]
A3=[exp(-2*pi*j*d*[0:6]*cos(q3)/lma)]
A4=[exp(-2*pi*j*d*[0:6]*cos(q4)/lma)]
A=[A1,A2,A3,A4] 得出A矩阵
n=1:1900
v1=.015 四信号的频率
v2=.05
v3=.02
v4=.035
d=[1.3*cos(v1*n) 1*sin(v2(we)
- 2010-05-06 15:26:50下载
- 积分：1
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bf_1500Hz_normal_statistic
声纳技术 常规的波束形成 信号形式：实信号,f0=1.5kHz，fs=15kHz 与带通采样等效。 统计方位估计性能与信噪比之间的关系，snr=0:30(Sonar technology)
- 2012-04-15 09:12:31下载
- 积分：1
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g
说明： this file along with others coded "finger" construct the complete source code for fingerprint recognition system. do enjoy using it,
- 2010-04-15 03:37:20下载
- 积分：1
