登录
首页 » matlab » PMSM

PMSM

于 2014-12-16 发布 文件大小:19KB
0 174
下载积分: 1 下载次数: 24

代码说明:

   Matlab simulation of PMSM with SPWM modulation. This is an example that use every single element of simulink library, so it can help you understand details of PMSM simulation. This simulation module was built by my own, any questions, pleases contact me.

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • Signal_Matlab
    《信号分析与处理_MATLAB语言及应用》,介绍了Matlab在信号分析与处理领域的应用。("Signal Analysis and Processing _MATLAB language and applications", Matlab introduced in signal analysis and processing fields.)
    2007-03-14 17:37:03下载
    积分:1
  • threephasePWMinverterusinguniversalbridge
    three phase system with sinosoidal inverter .check it with source code
    2013-07-25 15:53:26下载
    积分:1
  • dynamic-meterology-chapter-one--
    an introduction to dynamic meterology chapter five matlab所有代码 气象专业经典资料(an introduction to dynamic meterology chapter five matlab code)
    2013-12-11 18:35:39下载
    积分:1
  • PTRM
    本程序为被动时间反转镜的信道多途压缩的仿真程序(Passive Time Reversal Mirror)
    2016-01-06 21:02:48下载
    积分:1
  • l1ioftb2
    说明:  该算法非常适用于正系统、正切换系统等仿真(NUMERICAL SIMULATION FOR POSITIVE SYSTEMS and positive switched system)
    2018-12-24 16:10:25下载
    积分:1
  • somefunctiontosolveextremum
    说明:  目标函数的几种极值求解方法,包括最速下降法,拟牛顿法,共轭梯度法MATLAB实现(The objective function to solve several extreme methods, including steepest descent, quasi-Newton method, conjugate gradient method)
    2010-04-05 09:21:36下载
    积分:1
  • ID3-dision-tree-
    matlab 代码 机器学习算法 决策树算法id3算法 (matlab id3 算法)
    2013-11-04 17:32:23下载
    积分:1
  • wenbu3
    对光纤光栅应变传感器实现温度补偿,解决应变温度交叉敏感问题(FBG strain sensors for temperature compensation, to resolve cross-strain temperature sensitive issues)
    2014-04-04 22:04:26下载
    积分:1
  • LS_CCA
    回归分析工具,包含CCA,kernel CCA,LS-CCA及它们的变形,希望对同学们有用。(Regression analysis tools, including CCA, kernel CCA, LS-CCA and their variants , I hope useful to the students.)
    2016-07-03 21:52:26下载
    积分:1
  • c9_estimatepi
    %File: c9_estimatepi.m %有5个pi的估计,每一个都是基于500次重复随机试验,所得的pi的五个估计值用以下向量表示 %pi的估计值=[3.0960 3.0720 2.9920 3.1600 3.0480] %如果对5个结果进平均,则pi的估计值=3.0736,这样的结果等价于2500次的试验结果。( File: c9_estimatepi.m have 5 pi estimates are based on a randomized trial to repeat 500 times the income of the five estimated value of pi with the following vector, said the estimated value of pi = [3.0960 3.0720 2.9920 3.1600 3.0480] if the results into an average of 5, then the estimated value of pi = 3.0736, so the result is equivalent to 2500 times the test results.)
    2006-11-05 10:30:13下载
    积分:1
  • 696518资源总数
  • 106242会员总数
  • 10今日下载