登录
首页 » Visual C++ » TestCalculatorDemo

TestCalculatorDemo

于 2013-11-16 发布 文件大小:25342KB
0 269
下载积分: 1 下载次数: 3

代码说明:

  这是自己编写的一个简易计算器,用于加减乘除计算,还有百分比和平方。(I have written a simple calculator for arithmetic calculations, as well as percentages and square.)

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • ExcelOperate11
    vc读写excel,这个是用mfc写的,基于对话框的小程序(Vc u8BFB u5199excel)
    2017-05-25 11:34:36下载
    积分:1
  • 1
    说明:  1到33的任意6个数字,他们之和加起来是61,或者改掉sum数字,让他们和为你想要的数字(1 to33Any 6 numbers, and they add up to 61, or get rid of sum numbers, and make them as the number you want )
    2012-05-02 13:08:48下载
    积分:1
  • CBinary
    一个关于十六进制数组动态创建的方法,对使用者在编写通信帧的时候很有用(An array of dynamically created on hexadecimal method, the users in the preparation of the communication frame is useful when)
    2013-11-07 19:30:53下载
    积分:1
  • StringReplace
    永远替换字符串中的字符,和word中的替换功能相同(Forever the replacement string of characters, and word replacement functionality in the same)
    2008-03-26 12:57:27下载
    积分:1
  • tongxunlu
    简单的通讯录编程,基于c语言或C++,只有源码,喜欢的顶下(Simple address book program, based on c language or C++, only the source code, like the parietal)
    2011-06-05 19:16:12下载
    积分:1
  • code-
    从键盘接收字符串,并统计其中各种字符出现频率!(calculate the frequency of every sinal get from the keyboard!)
    2012-04-23 10:59:16下载
    积分:1
  • BookManager
    说明:  用VB 6.0 + SQL Server2000 编译写的图馆管理系统(Using VB 6.0 SQL Server2000 compiler written by library management system)
    2008-11-04 19:30:38下载
    积分:1
  • lr0
    lr(0)文法及其预测分析表 lr(0)文法及其预测分析表 lr(0)文法及其预测分析表(lr (0) Analysis and prediction of grammar lr (0) Analysis and prediction of grammar lr (0) grammar analysis and forecast table)
    2009-06-04 20:55:10下载
    积分:1
  • PI
    说明:  本程序是模拟常数PI的计算,可以精确到小数点后很多位!(This procedure is a simulation of constant PI calculation can be accurate to a lot of places after the decimal point!)
    2008-12-14 20:35:09下载
    积分:1
  • closest_pair
    分治法思想,求最邻近点对,考虑将所给的n个点的集合S分成2个子集S1和S2,每个子集中约有n/2个点,然后在每个子集中递归地求其最接近的点对(Divide and conquer ideas, find the nearest point to consider given the set S of n points into two subsets S1 and S2, each subset of about n/2 points, and then recursively find its focus in each sub-the closest point)
    2013-12-07 16:46:26下载
    积分:1
  • 696516资源总数
  • 106409会员总数
  • 8今日下载