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Qt_Flight
说明: 图形化界面,简易航线查询系统,数据源为压缩包内的.csv文件
求任意两个机场之间的最短飞行时间。
仅限直飞或 1 次中转,求任意两个机场的航线(航班 ID 顺序表)。
给定起飞时段或者降落时段或者机型要求,求任意两个机场的多个备选航线(航班 ID 顺序表)。
给定起飞时段或者降落时段或者机型要求,求任意两个机场之间的航费(机票价格)最低的路径。(Find the shortest flight time between any two airports.
Only direct flights or one transit are allowed, and the routes of any two airports (flight ID sequence table) are obtained.
Given the take-off time or landing time or aircraft type requirements, find multiple alternative routes (flight ID sequence table) for any two airports.
Given the take-off time or landing time or aircraft type requirements, find the lowest route between any two airports (ticket price).)
- 2020-12-25 22:59:04下载
- 积分:1
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sorting
该文件描述了排序算法的实验指导报告,通过本实验,你可以了解插入排序、选择排序、希尔排序、堆排序、冒泡、双向冒泡、快速排序、归并排序、递归的归并排序、基数排序等多种排序方法的实验(The document describes the experimental guidance of the sorting algorithm, through this experiment, you can learn about the insertion sort, selection sort, shell sort, heap sort, bubble, two-way bubble, quick sort, merge sort, merge sort recursive basesorting a variety of sorting methods experiment
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- 2012-06-08 11:28:55下载
- 积分:1
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xuanzexingjiegou
选择型结构c语言编程 (Choose the type of structure of C language programming)
- 2013-09-24 22:11:37下载
- 积分:1
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把中缀表达式转换成后缀表达式,输入中缀表达式输出后缀表达式...
把中缀表达式转换成后缀表达式,输入中缀表达式输出后缀表达式-Chinese sergeant expressions into expressions suffix, the importation of Chinese exports suffix sergeant expression expression
- 2022-03-25 09:14:31下载
- 积分:1
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在一个圆形操场的四周摆放着n堆石子。现要将石子有次序地合并成一堆。规定每次只能选相邻的两堆石子合并成新的一堆,并将新的一堆石子数记为该次合并的得分。试设计一个算...
在一个圆形操场的四周摆放着n堆石子。现要将石子有次序地合并成一堆。规定每次只能选相邻的两堆石子合并成新的一堆,并将新的一堆石子数记为该次合并的得分。试设计一个算法,计算出将n堆石子合并成一堆的最小得分和最大得分,并分析算法的计算复杂度。-in a circle around the playground are placed n gravel pile. Is a stone should order to be merged into a heap. Stipulated that only elected adjacent to the pile of gravel into the new heap, and a new pile of gravel credited for the combined scores. Design a test algorithm to calculate n heap into a pile of gravel to the minimum score and the biggest score and analysis of algorithm complexity.
- 2022-03-22 21:40:18下载
- 积分:1
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1。我用VC 6编写的程序,包括过程的顺序…
1.本程序由本人采用vc++ 6.0编写,包括了排序平衡二叉树的整套算法(包括插入、删除、查找以及其测试算法)。 2.运行myavl_vc.exe输入树的初始结点个数,确定后本程序将在内存中生成一棵相应结点数的二叉树,在此基础上你可以进行各种操作(插入、删除、查找以及测试其平衡性、排序性等) 3.每一个结点信息包括"商品编码"、"商品名称",且以"商品编码"作为关键字 4.初始生成的树的结点的商品编码为从1按顺序递增,商品名称为"生成的商品"加上商品编码 5.程序中的随机插入与随机删除是为了更好的测试程序的正确性和可靠性 6.随机插入(删除)时,程序将不断向(从)树中随机插入(删除)结点,每次随机插入(删除)都会进行平衡性与排序性的检查,如果树已经失去了有序性或平衡性,则会弹出树已失去了有序性或平衡性的提示并停止插入(删除)操作,当然你可以随时中断随机操作-1. The procedure I used vc 6.0 preparation, including the sequencing of the entire balanced binary tree algorithm (including insert, delete, search and test algorithm). 2. Running myavl_vc.exe importation of the initial tree node number, the procedures established in the memory of the formation of a corresponding nodes of a binary tree, and on this basis you can conduct various operations (insert, delete, search and testing their balance, sorting etc.) 3. each node information including "Product Codes," "trade names," and the "commodity codes" as the keyword 4. initial produ
- 2022-03-11 19:21:53下载
- 积分:1
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One of database applications: vehicle management system, using Visual FoxPro
数据库应用之一:车辆管理系统,用Visual FoxPro-One of database applications: vehicle management system, using Visual FoxPro
- 2022-11-22 18:55:03下载
- 积分:1
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仓储药房管理系统
仓储药房管理系统-warehousing pharmacy management system
- 2022-08-16 14:46:49下载
- 积分:1
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1,图的建立与遍历操作
建立图的邻接矩阵
输出图从顶点V0出发按深度优先遍历的顶点序列
输出图从顶点V0出发按广度优先遍历的顶点序列
2,图的建...
1,图的建立与遍历操作
建立图的邻接矩阵
输出图从顶点V0出发按深度优先遍历的顶点序列
输出图从顶点V0出发按广度优先遍历的顶点序列
2,图的建立与拓扑排序-1, Graph traversal operation with the establishment of the establishment of the adjacency matrix output plans starting from the vertex V0 by depth-first traversal sequence of vertices losers Figure out from the starting point V0 according to the breadth- first traversal sequence vertex 2, and plans to establish the topological sorting
- 2022-11-18 00:10:04下载
- 积分:1
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员工数据基
使用数据库的优点是相当大的。如果没有他们,你将很难找到一个体面的保持和管理信息系统。近年来,更大的灵活性和方便用户的数据库使这些系统关键业务组件。许多数据库解决方案是可用于任何类型的业务需求,从存储到 WordPress 博客的网络服务的客户信息矩阵。这里使用的是数据库的原因
- 2022-02-06 10:51:21下载
- 积分:1