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matlabfir
matlabfir 是一个用MATLAB设计FIR的程序，自己编的，如果有不当之处，希望斑竹帮忙看看(MATLAB importan easy)
- 2009-05-22 09:40:17下载
- 积分：1
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yichuan
遗传算法的matlab代码,适合初学者，大家相互学习吧(Genetic algorithm matlab code, suitable for beginners, learn from each other.)
- 2013-05-10 14:47:55下载
- 积分：1
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timing
sc-fde（单载波频域均衡）系统的定时功能仿真(sc-fde (single carrier frequency domain equalization) system timing functional simulation)
- 2010-08-04 20:53:30下载
- 积分：1
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linwenfu
图像处理 直方均衡等
最完整版本 包括VC++及其matlab实现
而且根据代码可以直接用matlab进行GUI界面编程(Image processing, such as straight balanced side including the most complete version of VC++ and matlab code to achieve and can be directly used in accordance with matlab interface to GUI programming)
- 2009-06-06 09:40:50下载
- 积分：1
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MATLABbian
MATLAB编程（第二版)
Stephen J. Chapman 著
邢树军 郑碧波译(MATLAB Programming (Second Edition) Stephen J. Chapman
translated by Xingshu Jun Zheng Bibo)
- 2011-01-19 21:14:36下载
- 积分：1
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bilinearqud
有限元中比例nearQuad单元的matlab程序(FEA matlab )
- 2013-10-11 20:23:02下载
- 积分：1
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matlabfirlvbo
matlab对语音信号进行滤波，使用fir低通滤波器(the speech signal matlab filter using FIR low-pass filter)
- 2013-04-30 08:53:14下载
- 积分：1
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MATLABIMAGEPROCESS
一本关于matlab入门不错的书籍， (Getting Started on a matlab good books,)
- 2007-08-27 19:44:22下载
- 积分：1
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juzhen
这是用四种方法写的矩阵相称问题，有传统的，有两种优化的，还有一种是分治法(This is a matrix with four ways to write the issue of proportionality, there are traditional, there are two kinds of optimization, there is a divide and conquer)
- 2010-12-14 10:52:19下载
- 积分：1
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YTY_GA_Final
To find the largest fitness value and its location
寻找最大适应性及相应的位置！ Population N=50；crossover bits=n/2 (half of bits of an individual) with random locations，mutation bits = 4 种群数 N=50，交换位数= n/2, 即个体位数的一半，且位置随机；
变异位数统一取为4；
Nc=20，28，36，44，individuals for crossover(交换的个数)。 Nm=1，5，10，15， individuals for mutation(变异的个数)。 (To find the largest fitness value and its location to find the location of the maximum adaptability and the corresponding! Population N = 50 crossover bits = n/2 (half of bits of an individual) with random locations, mutation bits = 4 population size N = 50, exchange digits = n/2, ie half of the median individual, and random position variation is taken as unity median 4 Nc = 20,28,36,44, individuals for crossover (exchange number). Nm = 1,5,10,15, individuals for mutation (the number of variations.))
- 2010-12-27 21:23:27下载
- 积分：1
